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3 years ago

7

What is 7,259 rounder to the nearest thousand?

1 answer:

Paul [167]3 years ago

7 0

The answer will be 7300

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doctors use gallium in scanning some patients for diseases the table shows the amount of gallium in mg remaining in a patients s

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Step-by-step explanation:

no sn as. kojsshsusishheidhsusjjsbsbshsbsjs7ehsjsnkosvsjsishshshsjdjjddyfygyvrcudjdhdudhsjsudhdjs

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3 years ago

HELP PLEASE :/ math is not my bff

gtnhenbr [62]

1. None of the answer choices are correct, because the length that were to go with those numbers don't fit. The answer is D.

2. One coffee cost $4 and a latte would cost $2.50, because the other prices for a cup of coffee would exceed the price of the total of two coffees plus one latte and three coffees plus two lattes. The answer is A: $4.00.

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3 years ago

Find the value of: (ii) [(1/4) -1 + (1/3) -2 - (1/2) -3 ] ÷ 5

Anastaziya [24]

Answer:

-71/6

Step-by-step explanation:

[(1/4) -1 + (1/3) -2 - (1/2) -3 ] ÷ 5

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[-71/12]/5

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3 years ago

(PLEASEEEEE HELPPP)Helen went with her mother to a fabric Sale. on the sale table, fabric was marked 25% off. The regular price

QveST [7]

I think the answer is 25.17

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3 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

uysha [10]

Answer:

$(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743$

$(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926$

And we are 9% confidence that the true mean for the difference of the population means is given by:

$0.0743 \leq \mu_1 -\mu_2 \leq 1.926$

Step-by-step explanation:

For this problem we have the following data given:

$\bar X_1 = 9$ represent the sample mean for one of the departments

$\bar X_2 = 8$ represent the sample mean for the other department

$n_1 = 25$ represent the sample size for the first group

$n_2 = 20$ represent the sample size for the second group

$s_1 = 2$ represent the deviation for the first group

$s_2 =1$ represent the deviation for the second group

Confidence interval

The confidence interval for the difference in the true means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

The confidence given is 95% or 9.5, then the significance level is $\alpha=0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df=n_1 +n_2 -2= 20+25-2= 43$

And the critical value for this case is $t_{\alpha/2}=2.02$

And replacing we got:

$(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743$

$(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926$

And we are 9% confidence that the true mean for the difference of the population means is given by:

$0.0743 \leq \mu_1 -\mu_2 \leq 1.926$

4 0

3 years ago