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jonny [76]
3 years ago
8

In a nuclear reactor, neutrons released by nuclear fission must be slowed down before they can trigger additional reactions in o

ther nuclei. To see what sort of material is most is most effective in slowing (or moderating) a neutron, calculate the ratio of a neutron's final kinetic energy to its initial kinetic energy for a head-on elastic collision with each of the following stationary target particle; (Note: the mass of a neutron is m = 1.009 u, where the atomic mass unit 1 u = 1.66*10^-27 kg)
(a) An electron (M = 5.49*10^-4 u)
(b) A proton (M = 1.007u)
(c) The nucleus of a lead atom (M = 207.2 u)
2. Based on your calculations in part 1, which material is the best moderator for neutrons?
Physics
2 answers:
ELEN [110]3 years ago
7 0

Answer:

neutron of mass m1,

Vf = Vi * (m1 - m2)/(m1 + m2)

m2 is the mass of the particle it collides with.

will be in collisions with protons.

Explanation:

dlinn [17]3 years ago
3 0

Answer:

For the colliding neutron of mass m1,

Vf = Vi * (m1 - m2)/(m1 + m2)

m2 is the mass of the particle it collides with.

The largest mass loss will be in collisions with protons.

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