Answer:
a) The rotational inertia when it passes through the midpoints of opposite sides and lies in the plane of the square is 16.8 kg m²
b) I = 50.39 kg m²
c) I = 16.8 kg m²
Explanation:
a) Given data:
m = 0.98 kg
a = 4.14 * 4.14
The moment of inertia is:

For 4 particles:

b) Distance from top left mass = x = a/2
Distance from bottom left mass = x = a/2
Distance from top right mass = x = √5 (a/2)
The total moment of inertia is:

c)

Answer:
Explanation:
Draw a free body diagram for the painter. There are three forces acting on him. The tension in the rope pulling him up, the normal force of the chair pushing him up, and gravity pulling him down.
Apply Newton's second law:
∑F = ma
T + N - W = ma
Since the painter is at rest, a = 0.
T + N - W = 0
T = W - N
T = Mg - N
Now draw a free body diagram of the chair. The chair has three forces acting on it also. The tension in the rope pulling it up, the normal force pushing down, and gravity pulling down.
Newton's second law for the chair:
∑F = ma
T - W - N = ma
Since the chair is also not accelerating, a = 0:
T - W - N = 0
T = W + N
T = mg + N
Now we have two equations and two variables. If we add the equations together, we can eliminate N:
2T = Mg + mg
2T = (M + m) g
T = (M + m) g / 2
Given that M = 55 kg, m = 10 kg, and g = 9.8 m/s²:
T = (55 + 10) (9.8) / 2
T = 318.5 N
If we round to two sig-figs, the tension in the rope is 320 N.
Answer:
You have to sub x in for the number you dont know and then solve for x.
Explanation:
10(5+x)=90
50+10x=90
10x=40
x=4
Answer:
a)15077 W
b)20.2185 horse power
Explanation:
P=F*V
F=ma
a=Vf-VS/t
Vf=28m/s
t=5.2
a=28/5.2
a=5.384 m/s²
F=100kg*5.384m/s²
F=538.4 N
P=F*V
P=538.4N*28m/s
P=15077 W=20.2185 horse power
1W=0.00134 Horse power
· free fall is any motion of a body where gravity is the only forceacting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.