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3 years ago

Name an altitude for ABC

Mathematics

2 answers:

valina [46]3 years ago

8 0

Altitude is another word for height so it would be the first answer

VikaD [51]3 years ago

3 0

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

ABC is a triangle.

And we need to find the altitude of a triangle.

Altitude of a triangle is a line segment from a vertex and it is perpendicular to the base.

So, It must be perpendicular.

So, According to graph, AF is the required altitude of ΔABC.

Hence, First option is correct.

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Multiply 0.006 by 3.08. Express in standard form

olga_2 [115]

Answer:

1.848 × 10^-2

Step-by-step explanation:

0.006 = 6 × 10^-3

3.08 = 3.08 × 10^0 (10^0 is equal to 1)

(6 × 10^-3) × (3.08 × 10^0) = 18.48 × 10^-3 = 1.848 × 10^-2

8 0

2 years ago

Write a paragraph to help Miguel explain to Hannah how to complete the problems. Be sure to explain the process step-by-step (re

Eddi Din [679]

Steps in multiplying fractions. Remember: finding common denominator is not necessary in multiplying fractions.
Common denominators are only needed in adding and subtracting fractions.

14/15 * 5/2

Step 1. Multiply the numerators.
14 * 5 = 70
Step 2. Multiply the denominators
15 * 2 = 30
Step 3. Simplify the fraction.
70/30 = 2 10/30 = 2 1/3

*the fraction 10/30 can still be simplified by dividing both numbers by 10. Hence, 1/3.

Steps in Dividing fractions.

24/60 ÷ 8/15

Step 1. Get the reciprocal of the 2nd fraction. Reciprocal means the reverse of the fraction. Simply swap the places of the numbers.

Reciprocal of 8/15 is 15/8.

Step 2. Multiply the 1st fraction to the reciprocal of the 2nd fraction. Follow steps in multiplying fractions.

24/60 * 15/8 = (24*15) / (60*8) = 360/480

Step 3. Simplify the fraction.
360/480 = 9 / 12 = 3/4

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4 0

3 years ago

Write 4 1/5 as a improper fraction

BartSMP [9]

Answer:

21/5

Step-by-step explanation:

8 0

3 years ago

Find the area of the following<br> kite:<br> A = [?] m²<br> 40 m<br> 16 m<br> 16 m<br> 6 m

Rama09 [41]

Answer:

$Area_{kite}=736m^2$

Step-by-step explanation:

There are a few methods to find the area of this figure:

1. kite area formula

2. 2 triangles (one top, one bottom)

3. 2 triangles (one left, one right)

4. 4 separate right triangles.

<h3><u>Option 1: The kite area formula</u></h3>

Recall the formula for area of a kite: $Area_{kite}=\frac{1}{2} d_{1}d_{2}$ where d1 and d2 are the lengths of the diagonals of the kite ("diagonals" are segments that connect non-adjacent vertices -- in a quadrilateral, vertices that are across from each other).

If you've forgotten why that is the formula for the area of a kite, observe the attached diagram: note that the kite (shaded in) is half of the area of the rectangle that surrounds the kite (visualize the 4 smaller rectangles, and observe that the shaded portion is half of each, and thus the area of the kite is half the area of the large rectangle).

The area of a rectangle is $Area_{rectangle}=bh$ , sometimes written as $Area_{rectangle}=bh$ , where w is the width, and h is the height of the rectangle.

In the diagram, notice that the width and height are each just the diagonals of the kite. So, the <u>Area of the kite</u> is <u>half of the area of that surrounding rectangle</u> ... the rectangle with sides the lengths of the kite's diagonals.Hence, $Area_{kite}=\frac{1}{2} d_{1}d_{2}$

For our situation, each of the diagonals is already broken up into two parts from the intersection of the diagonals. To find the full length of the diagonal, add each part together:

For the horizontal diagonal (which I'll call d1): $d_{1}=40m+6m=46m$

For the vertical diagonal (which I'll call d2): $d_{2}=16m+16m=32m$

Substituting back into the formula for the area of a kite:

$Area_{kite}=\frac{1}{2} d_{1}d_{2}\\Area_{kite}=\frac{1}{2} (46m)(32m)\\Area_{kite}=736m^2$

<h3><u /></h3><h3><u>Option 2: The sum of the parts (version 1)</u></h3>

If one doesn't remember the formula for the area of a kite, and can't remember how to build it, the given shape could be visualized as 2 separate triangles, the given shape could be visualized as 2 separate triangles (one on top; one on bottom).

Visualizing it in this way produces two congruent triangles. Since the upper and lower triangles are congruent, they have the same area, and thus the area of the kite is double the area of the upper triangle.

Recall the formula for area of a triangle: $Area_{triangle}=\frac{1}{2} bh$ where b is the base of a triangle, and h is the height of the triangle <em>(length of a perpendicular line segment between a point on the line containing the base, and the non-colinear vertex)</em>. Since all kites have diagonals that are perpendicular to each other (as already indicated in the diagram), the height is already given (16m).

The base of the upper triangle, is the sum of the two segments that compose it: $b=40m+6m=46m$

<u>Finding the Area of the upper triangle</u> $Area_{\text{upper }triangle}=\frac{1}{2} (46m)(16m) = 368m^2$

<u>Finding the Area of the kite</u>

$Area_{kite}=2*(368m^2)$

$Area_{kite}=736m^2$

<h3><u>Option 3: The sum of the parts (version 2)</u></h3>

The given shape could be visualized as 2 separate triangles (one on the left; one on the right). Each triangle has its own area, and the sum of both triangle areas is the area of the kite.

<em>Note: In this visualization, the two triangles are not congruent, so it is not possible to double one of their areas to find the area of the kite.</em>

The base of the left triangle is the vertical line segment the is the vertical diagonal of the kite. We'll need to add together the two segments that compose it: $b=16m+16m=32m$ . This is also the base of the triangle on the right.

<u>Finding the Area of left and right triangles</u>

$Area_{\text{left }triangle}=\frac{1}{2} (32m)(40m) = 640m^2$

The base of the right triangle is the same length as the left triangle: $Area_{\text{right }triangle}=\frac{1}{2} (32m)(6m) = 96m^2$

<u>Finding the Area of the kite</u>

$Area_{kite}=(640m^2)+(96m^2)$

$Area_{kite}=736m^2$

<h3><u>Option 4: The sum of the parts (version 3)</u></h3>

If you don't happen to see those composite triangles from option 2 or 3 when you're working this out on a particular problem, the given shape could be visualized as 4 separate right triangles, and we're still given enough information in this problem to solve it this way.

<u>Calculating the area of the 4 right triangles</u>

$Area_{\text{upper left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2$

$Area_{\text{upper right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2$

$Area_{\text{lower left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2$

$Area_{\text{lower right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2$

<u>Calculating the area of the kite</u>

$Area_{kite}=(320m^2)+(48m^2)+(320m^2)+(48m^2)$

$Area_{kite}=736m^2$

8 0

2 years ago

Why is -7 an integer but not a natural number?

MrMuchimi

Answer:

Natural Numbers are basically "counting numbers". If I ask you to start counting, you'll start at 1, then 2, then 3, and so on. It doesn't include 0 or any negative numbers because you wouldn't start from -10 when asked to count.

<h3>brainliest is appreciated :)</h3>

3 0

3 years ago

Read 2 more answers