<span>10 < –2b or 2b + 3 > 11 represents 2 different sets of numbers.
</span><span>10 < –2b can be reduced by dividing both sides by -2; you must then reverse the direction of the < sign: -5 > b, which is the interval b < -5: (-infinity, -5).
</span>2b + 3 > 11 reduces to 2b > 8, which in turn reduces to b > 4: (4, infinity).
It may be helpful to graph these sets.
If you really do mean "<span>10 < –2b or 2b + 3 > 11," then the "solution" is made up of two sub-intervals: b < -5 and b > 4.
</span>
Answer:
Hello !
The solutions are: -8 , -4 , 6
Hope this helps !
Given:
You know that:
In order to solve the operation, you can follow these steps:
1. Distribute the negative signs. Remember the Sign Rules for Multiplication:
Then:
2. Combine the like terms (add the Real Parts and add the Imaginary Parts):
Hence, the answer is: Option B.
