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Evgesh-ka [11]
3 years ago
9

The SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission proc

ess in the Cesium atom. Calculate the wavelength of this radiation (to 3 sig figs). In which region of the electromagnetic spectrum is the wavelength found?
Chemistry
2 answers:
Vlad [161]3 years ago
8 0

Answer :  The wavelength of this radiation is, 3.26\times 10^{-2}m and in microwave region, the electromagnetic spectrum the wavelength is found.

Explanation : Given,

Frequency of radiation = 9192631770s^{-1}

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of radiation

\lambda = wavelength of radiation

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

9192631770s^{-1}=\frac{3\times 10^8m/s}{\lambda}

\lambda=3.26\times 10^{-2}m

Thus, the wavelength of this radiation is, 3.26\times 10^{-2}m and in microwave region, the electromagnetic spectrum the wavelength is found.

elixir [45]3 years ago
4 0
For waves:
speed = frequency x wavelength
speed = 3 x 10⁸ 
frequency = 9192631770 Hz
wavelength = 3 x 10⁸ / (9192631770)
wavelength = 0.033 meters
This wavelength lies in the region of microwaves. 
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Answer: option (3) CuO + CO ⇄ Cu + CO₂


Explanation:


1) A redox reaction is an oxidation-reduction reaction.


2) An oxidation-reduction reaction is one in which at least one species is oxidized and other (or others) is reduced.


3) Oxidation is the increase on the oxidation number, which occurs by releasing electrons.


4) Reduction is the decrease of the oxidation number, which occurs by gaining electrons.


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As Cu is combined with O, CuO, in the reactant side of the chemical equation, then its oxidation number is not 0. Indeed, the rule is that in the formula CuO the oxidation states of Cu and O add up 0, and since the oxidation number of O is 2-, the oxidation number of Cu is 2+.


Therefore, having Cu changed its oxidation state from 2+ to 0, it was reduced, and this is a redox reaction.


Of course other atoms had to be oxidized. It was C whose oxidation state went from 2+ in CO to 4+ in CO₂.

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