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Aleksandr [31]
4 years ago
13

Different isotopes of a particular element contain the same number of

Chemistry
1 answer:
zimovet [89]4 years ago
8 0
Electrons and protons, but not neutrons.
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What mass of PCl5 will be produced from the given masses of both reactants? Express your answer to three significant figures and
UkoKoshka [18]

69 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

P₄ + 10Cl₂ → 4PCl₅

<h3>How to calculate the number of moles ?</h3>

To calculate the number of moles used the formula

Number of moles = \frac{\text{Given Mass}}{\text{Molar mass}}

Number of moles of P₄ = \frac{\text{Mass of}\ P_4}{\text{Molar mass of}\ P_4}

                                       = \frac{28\ g}{124\ g/mol}

                                       = 0.225 mol

Number of moles of Cl₂ = \frac{\text{Mass of}\ Cl_2}{\text{Molar mass of}\ Cl_2}

                                        = \frac{51\ g}{71\ g/mol}

                                        = 0.831 mol

From the balanced chemical equation we can say that the ratio of P₄ and Cl₂ is 1 : 10.

Ratio of P₄: 0.2260: 1  = 0.2260

Ratio of Cl₂:  0.8310: 10 =  0.08310

Because ratio of Cl₂ ratio smaller than P₄ becomes the limiting reactants

So mole of PCl₅ is based on mole of Cl₂

From the coefficient of reaction:

mol PCl₅: mol Cl₂ = 4: 10

Mole of PCl₅ = \frac{4}{10} \times 0.8310

                     = 0.3324

Molar mass of PCl₅= 208.5

Mass of PCl₅ = mole × molar mass

Mass of PCl₅ = 0.3324 × 208.5

Mass of PCl₅ = 69 gram

Thus from the above conclusion we can say that 69 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.

Learn more about the Number of moles here: brainly.com/question/15356425

#SPJ4

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What mass of PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂ ?

8 0
2 years ago
What is the molality of a solution containing 2.6 moles of sugar and 6 kg water?
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Convert kg into L, then take the moles and divide it by the L of water

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SOMEONE PLZ HELP Draw the Bohr-Rutherford diagram of magnesium( -26)
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Refer to the attachment

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The first step of crystal formation is nucleation<br><br> Is this true or false?
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3 years ago
At a pressure of 9.25×10−14 atm and an ordinary temperature of 300.0 K , how many molecules are present in a volume of 1.10 cm3
statuscvo [17]

Answer:

2.49 × 10⁶ molecules

Explanation:

Given data

  • Pressure (P): 9.25 × 10⁻¹⁴ atm
  • Temperature (T): 300.0 K
  • Volume (V): 1.10cm^{3} .\frac{1mL}{1cm^{3}} .\frac{1L}{1000mL} =1.10\times 10^{-3} L

We can calculate the moles of gas using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 9.25 × 10⁻¹⁴ atm × 1.10 × 10⁻³ L / (0.0821 atm.L/mol.K) × 300.0 K

n = 4.13 × 10⁻¹⁸ mol

1 mole contains 6.02 × 10²³ molecules (Avogadro's number). The number of molecules in 4.13 × 10⁻¹⁸ moles is:

4.13 × 10⁻¹⁸ mol × (6.02 × 10²³ molecule/1 mol) = 2.49 × 10⁶ molecule

7 0
3 years ago
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