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Pepsi [2]
3 years ago
10

Naturally occurring boron has an atomic weight of 10.811. Its principal isotopes are 10B and 11B. Part A What is the abundance (

in atomic percent) of each isotope

Chemistry
1 answer:
Darya [45]3 years ago
4 0

Answer:

10B has 18.9%

11B has 81.1%

Explanation:Please see attachment for explanation

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How many atoms are in 3.05 grams of copper?
vfiekz [6]

6.02 x10^23 atom  

3.5g x 1mol/63.55g Cu x 6.02 x 10^23/ 1mol=

3.32 x 10^22 atoms

5 0
3 years ago
density of a piece of ebony wood is 1.174 g/ml. what is the volume in quarts of a 2.1549 lb piece of this ebony wood?
lapo4ka [179]

0.88qt

Explanation:

Given parameters:

Density of ebony wood = 1.174g/ml

Mass of wood = 2.1549lb

Unknown:

Volume of the wood in quarts = ?

Solution:

Density is defined as the mass per unit volume of a substance.

Mass is the quantity of matter the wood contains.

Volume is the space it occupies.

To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.

Then convert the volume from mL to quarts.

 Density = \frac{mass}{volume}

 Volume = \frac{mass}{density}

    1 pound = 453.592g

   2.1549 lb =  2.1549 x 453.592 = 977.5g

Volume = \frac{977.5}{1.174} = 832.6mL

     1 quart = 946.353mL

        Therefore 832.6mL x \frac{1qt}{946.353} = 0.88qt

learn more:

Density brainly.com/question/8441651

#learnwithBrainly

7 0
3 years ago
If a gas occupies 79.5 mL at -1.4°C, what temperature, in Kelvin, would it
Anna35 [415]

Answer:

121 K

Explanation:

Step 1: Given data

  • Initial volume (V₁): 79.5 mL
  • Initial temperature (T₁): -1.4°C
  • Final volume (V₂): 35.3 mL

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

5 0
3 years ago
Which is true about models in science
levacccp [35]
Models in science help you get the idea of what something looks like that's why your teacher may ask you to draw a diagram to help you remember what the object looks like. Hope this helps.
6 0
3 years ago
Iodine-131 decays with a half-life of 8.02
dlinn [17]
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
3 0
3 years ago
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