Question

Aggregate blend composed of 65% coarse aggregate (SG 2.701), 35% fine aggregate (SG 2.625)

Answer 1

Answer:

• 2.674
• 2.428
• 91.695%
• 2.592
• 3.305%
• 11.786%
• 78.1%

Explanation:

coarse aggregate (ca) = 65%,   SG = 2.701

Fine aggregate = 35%,    SG = 2.625

A) Bulk specific gravity of aggregate

   = $\frac{65*2.701 + 35*2.625}{100} = 2.674$

B) Wm = 1257.9 g { weight in air }

    Ww = 740 g { submerged weight }

   therefore Bulk specific gravity of compacted specimen

   = $\frac{Wm}{Wm-Ww}$  =  $\frac{1257.9}{1257.9 - 740 }$  =  2.428

   Theoretical specific gravity = 2.511

Percent stone

= 100 - asphalt content - Vv

= 100 - 5 - 3.305 = 91.695%

c) percent of void

= $\frac{9.511-2.428}{2.511} * 100$    Vv = 3.305%

d) let effective specific gravity in stone

     = $\frac{91.695*unstone+ 5 *1.030 }{96.695} = 2.511$

    = Instone = 2.592 effective specific gravity of stone

e) Vv = 3.305%

f ) volume filled with asphalt (Vb) = $\frac{\frac{Wb}{lnb} }{\frac{Wm}{Inm} } * 100$

           Vb = $\frac{5 * 2.428}{1.030 * 100} * 100$

          Vb = 11.786 %

Volume of mineral aggregate = Vb + Vv

              VMA = 11.786 + 3.305 = 15.091

g) percent void filled with alphalt

     = Vb / VMA * 100

    VMA = 11.786 + 3.305 = 15.091

   percent void filled with alphalt

     = Vb / VMA * 100 = (11.786 / 15.091) * 100 = 78.1%