Answer:
Batteries work by storing negative photons on one side then transfering them to the positive side and everything thats inbetween
Explanation:
Answer:
q₀ = 350,740.2885 N/m
Explanation:
Given
![q(x)=\frac{x}{L} q_{0}](https://tex.z-dn.net/?f=q%28x%29%3D%5Cfrac%7Bx%7D%7BL%7D%20q_%7B0%7D)
σ = 120 MPa = 120*10⁶ Pa
![L=4 m\\w=200 mm=0.2m\\h=300 mm=0.3m\\q_{0}=? \\](https://tex.z-dn.net/?f=L%3D4%20m%5C%5Cw%3D200%20mm%3D0.2m%5C%5Ch%3D300%20mm%3D0.3m%5C%5Cq_%7B0%7D%3D%3F%20%5C%5C)
We can see the pic shown in order to understand the question.
We apply
∑MB = 0 (Counterclockwise is the positive rotation direction)
⇒ - Av*L + (q₀*L/2)*(L/3) = 0
⇒ Av = q₀*L/6 (↑)
Then, we apply
![v(x)=\int\limits^L_0 {q(x)} \, dx\\v(x)=-\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6} \\M(x)=\int\limits^L_0 {v(x)} \, dx=-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x](https://tex.z-dn.net/?f=v%28x%29%3D%5Cint%5Climits%5EL_0%20%7Bq%28x%29%7D%20%5C%2C%20dx%5C%5Cv%28x%29%3D-%5Cfrac%7Bq_%7B0%7D%7D%7B2L%7D%20x%5E%7B2%7D%2B%5Cfrac%7Bq_%7B0%7D%20L%7D%7B6%7D%20%5C%5CM%28x%29%3D%5Cint%5Climits%5EL_0%20%7Bv%28x%29%7D%20%5C%2C%20dx%3D-%5Cfrac%7Bq_%7B0%7D%7D%7B6L%7D%20x%5E%7B3%7D%2B%5Cfrac%7Bq_%7B0%7D%20L%7D%7B6%7Dx)
Then, we can get the maximum bending moment as follows
![M'(x)=0\\ (-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x)'=0\\ -\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6}=0\\x^{2} =\frac{L^{2}}{3}\\ x=\sqrt{\frac{L^{2}}{3}} =\frac{L}{\sqrt{3} }=\frac{4}{\sqrt{3} }m](https://tex.z-dn.net/?f=M%27%28x%29%3D0%5C%5C%20%28-%5Cfrac%7Bq_%7B0%7D%7D%7B6L%7D%20x%5E%7B3%7D%2B%5Cfrac%7Bq_%7B0%7D%20L%7D%7B6%7Dx%29%27%3D0%5C%5C%20-%5Cfrac%7Bq_%7B0%7D%7D%7B2L%7D%20x%5E%7B2%7D%2B%5Cfrac%7Bq_%7B0%7D%20L%7D%7B6%7D%3D0%5C%5Cx%5E%7B2%7D%20%3D%5Cfrac%7BL%5E%7B2%7D%7D%7B3%7D%5C%5C%20%20x%3D%5Csqrt%7B%5Cfrac%7BL%5E%7B2%7D%7D%7B3%7D%7D%20%3D%5Cfrac%7BL%7D%7B%5Csqrt%7B3%7D%20%7D%3D%5Cfrac%7B4%7D%7B%5Csqrt%7B3%7D%20%7Dm)
then we get
![M(\frac{4}{\sqrt{3} })=-\frac{q_{0}}{6*4} (\frac{4}{\sqrt{3} })^{3}+\frac{q_{0} *4}{6}(\frac{4}{\sqrt{3} })\\ M(\frac{4}{\sqrt{3} })=-\frac{8}{9\sqrt{3} } q_{0} +\frac{8}{3\sqrt{3} } q_{0}=\frac{16}{9\sqrt{3} } q_{0}m^{2}](https://tex.z-dn.net/?f=M%28%5Cfrac%7B4%7D%7B%5Csqrt%7B3%7D%20%7D%29%3D-%5Cfrac%7Bq_%7B0%7D%7D%7B6%2A4%7D%20%28%5Cfrac%7B4%7D%7B%5Csqrt%7B3%7D%20%7D%29%5E%7B3%7D%2B%5Cfrac%7Bq_%7B0%7D%20%2A4%7D%7B6%7D%28%5Cfrac%7B4%7D%7B%5Csqrt%7B3%7D%20%7D%29%5C%5C%20M%28%5Cfrac%7B4%7D%7B%5Csqrt%7B3%7D%20%7D%29%3D-%5Cfrac%7B8%7D%7B9%5Csqrt%7B3%7D%20%7D%20q_%7B0%7D%20%2B%5Cfrac%7B8%7D%7B3%5Csqrt%7B3%7D%20%7D%20q_%7B0%7D%3D%5Cfrac%7B16%7D%7B9%5Csqrt%7B3%7D%20%7D%20q_%7B0%7Dm%5E%7B2%7D)
We get the inertia as follows
![I=\frac{w*h^{3} }{12} \\ I=\frac{0.2m*(0.3m)^{3} }{12}=4.5*10^{-4}m^{4}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7Bw%2Ah%5E%7B3%7D%20%7D%7B12%7D%20%5C%5C%20I%3D%5Cfrac%7B0.2m%2A%280.3m%29%5E%7B3%7D%20%7D%7B12%7D%3D4.5%2A10%5E%7B-4%7Dm%5E%7B4%7D)
We use the formula
σ = M*y/I
⇒ M = σ*I/y
where
![y=\frac{h}{2} =\frac{0.3m}{2}=0.15m](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bh%7D%7B2%7D%20%3D%5Cfrac%7B0.3m%7D%7B2%7D%3D0.15m)
If M = Mmax, we have
![(\frac{16}{9\sqrt{3} }m^{2} ) q_{0}\leq \frac{120*10^{6}Pa*4.5*10^{-4}m^{4} }{0.15m}\\ q_{0}\leq 350,740.2885\frac{N}{m}](https://tex.z-dn.net/?f=%28%5Cfrac%7B16%7D%7B9%5Csqrt%7B3%7D%20%7Dm%5E%7B2%7D%20%29%20q_%7B0%7D%5Cleq%20%5Cfrac%7B120%2A10%5E%7B6%7DPa%2A4.5%2A10%5E%7B-4%7Dm%5E%7B4%7D%20%20%20%7D%7B0.15m%7D%5C%5C%20q_%7B0%7D%5Cleq%20350%2C740.2885%5Cfrac%7BN%7D%7Bm%7D)
Answer:
![K_f = 1.422](https://tex.z-dn.net/?f=K_f%20%3D%201.422)
Explanation:
We know that relationship between fatigue and stress concentration factor
![K_f = 1+q(K_t-1)](https://tex.z-dn.net/?f=K_f%20%3D%201%2Bq%28K_t-1%29)
Where
=fatigue concentration factor
=stress concentration factor
q=Notch sensitivity
Here D/d=2 and r/d=0.125
Now from standard design data book ![K_t=1.79](https://tex.z-dn.net/?f=K_t%3D1.79)
For Sut=440 MPa and r= 4 mm
q=0.8
Now by putting the values
![K_f = 1+q(K_t-1)](https://tex.z-dn.net/?f=K_f%20%3D%201%2Bq%28K_t-1%29)
![K_f = 1.8(1.79-1)](https://tex.z-dn.net/?f=K_f%20%3D%201.8%281.79-1%29)
![K_f = 1.422](https://tex.z-dn.net/?f=K_f%20%3D%201.422)
Ummmmmmm do u need help with anything ✌?
1.) A semiconductor is a device whose conductivity lies between the conductivity of the conductors and the insulators.
2.) A Zener diode is a semiconductor device made of silicon that allows current to flow in both directions.
<h3>What is a semiconductor?</h3>
A semiconductor is a device whose conductivity lies between the conductivity of the conductors and the insulators.
Due to the inclusion of an impurity or temperature effects, a solid substance with conductivity between that of an insulator and that of most metals. Semiconductor devices, particularly silicon devices, are key components of most electronic circuits.
Zener diode:-
A Zener diode is a semiconductor device made of silicon that allows current to flow in both directions.
To know more about semiconductors follow
brainly.com/question/13800609
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