1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Softa [21]
4 years ago
15

A differential amplifier is very useful for removing common mode noise voltage that might be fed or induced in the signal cables

. Suppose the input signal coming from a signal wire is Vs. Because of potential corruption in the measurement circuit, a common mode noise Vn is induced. In this case, the input voltages at both input wires become Vs Vn at the inverting input and Vn at the non-inverting input. Derive the circuit transfer equation and give the condition for removal of common mode noise.
Engineering
1 answer:
Reptile [31]4 years ago
7 0
Texas Instruments Incorporated and its subsidiaries (TI) reserve the right to make corrections, modifications, enhancements, improvements, and other changes to its products and services at any time and to discontinue any product or service without notice. Customers should obtain the latest relevant information before placing orders and should verify that such information is current and complete. All products are sold subject to TI’s terms and conditions of sale supplied at the time of order acknowledgment.
TI warrants performance of its hardware products to the specifications applicable at the time of sale in accordance with TI’s standard warranty. Testing and other quality control techniques are used to the extent TI deems necessary to support this warranty. Except where mandated by government requirements, testing of all parameters of each product is not necessarily performed.
TI assumes no liability for applications assistance or customer product design. Customers are responsible for their products and applications using TI components. To minimize the risks associated with customer products and applications, customers should provide adequate design and operating safeguards.
TI does not warrant or represent that any license, either express or implied, is granted under any TI patent right, copyright, mask work right, or other TI intellectual property right relating to any combination, machine, or process in which TI products or services are used. Information published by TI regarding third party products or services does not constitute a license from TI to use such products or services or a warranty or endorsement thereof. Use of such information may require a license from a third party under the patents or other intellectual property of that third party, or a license from TI under the patents or other intellectual property of TI.
Reproduction of information in TI data books or data sheets is permissible only if reproduction is without alteration and is accompanied by all associated warranties, conditions, limitations, and notices. Reproduction of this information with alteration is an unfair and deceptive business practice. TI is not responsible or liable for such altered documentation.
Resale of TI products or services with statements different from or beyond the parameters stated by TI for that product or service voids all express and any implied warranties for the associated TI product or service and is an unfair and deceptive business practice. TI is not responsible or liable for any such statements.
I think will help
You might be interested in
if you want to withdraw $10000 at the end of two years and $35000 at the end of four years, how much should you deposit now into
Katen [24]

Answer:

490000 dollars

Explanation:

3 0
2 years ago
The article provides information by using a list. What does it list? A. Thanksgiving food B. places where clams can be found C.
Gelneren [198K]

Answer:

C

Explanation:

7 0
4 years ago
A displacement transducer has the following specifications: Linearity error ± 0.25% reading Drift ± 0.05%/○C reading Sensitivity
White raven [17]

Answer:

The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm

Explanation:

uncertainty in a nominal displacement

= (u^2 + v^2)^(1/2)

assume from specifications that k = 5v/5cm

                                                         = 1v/cm

u^2 = (0.0025*2)^(2) + (0.005*10*2)^2 + (0.0025*2)^2

      = 0.01225v

v = 2v * 0.001

  = 0.002v

uncertainty in a nominal displacement

= (u^2 + v^2)^(1/2)

= ((0.01225)^2 + (0.002)^2)^(1/2)

= 0.0124 cm

Therefore, The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm

8 0
3 years ago
Convert mechanical energy into electric energy. What can he use?
Nina [5.8K]

Answer:

<h2>Generator </h2>

Explanation:

A generator converts mechanical energy into electrical energy

7 0
4 years ago
On a summer day in New Orleans, Louisiana, the pressure is 1 atm: the temperature is 32°C; and the relative humidity is 95 perce
FinnZ [79.3K]

Answer:

Δw =7.95 kg/1000m^3

q = 62362.3 kg/1000m^3

Explanation:

To solve this problem we first need to use the psycrometric chart to determine the enthalpy h1, specific volume vi and absolute humidity col by using the given temperature T1 = 32°C and the relative humidity Ф1 = 95%.  

h_1 =  106.5 kJ/kg

v_1 = 0.91 m^3/kg

w_1 = 0.02905

We will also need the enthalpy h2 and the absolute humidity w_2 at the exit point. We will again use the pyscrometric chart and the given temperature T_2 = 24°C. From the problem we also know that the exit relative humidity is = 60%.  

h2 = 52.6 kJ/kg

w_2 = 0.01119

We need to express the final results in units per 1000 m^3. To do that we will need the mass m of this volume of air V and to calculate that we will use the given pressure p = 1 atm = 101.3 kPa.  

m = R_a*T_1/V.p

m = 1000*101.3/0.287*305K

m = 1157 kg

Because it is a closed system, the amount of water removed Δw can be calculated as:  

Δw =w_1 - w_2

Δw =0.02905- 0.01119

Δw =0.00687 kg/kg* 1157kg/1000m^3

Δw =7.95 kg/1000m^3

From the energy balance equation we can calculate the specific heat q removed from the air.  

q = h_1 - h_2

q = 106.5 kJ/kg - 52.6 kJ/kg

q = 53.9 kJ/kg * 1157kg/1000m^3

q = 62362.3 kg/1000m^3

3 0
4 years ago
Other questions:
  • Definition of permanent, semi permanent and temporary heat setting
    5·1 answer
  • Code scramble: make the program sort the three numbers x, y and z into increasing order, so that x has the smallest value, y has
    8·1 answer
  • 2. The soil borrow material to be used to construct a highway embankment has a mass unit weight of 110.0 pcf, a water content of
    11·1 answer
  • Technician A say's that The most two-stroke engines have a pressure type lubrication system. Technician be says that four stroke
    11·1 answer
  • Which section of business plan should be the bulk of the plan
    7·1 answer
  • Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the accoun
    10·2 answers
  • Unlike in a reguler panel, in a subpanel, the neutral bus must be completely isolated from the
    12·1 answer
  • Every time I take a photo, that photo has to be stored in a file somewhere within "My Files" correct?
    15·2 answers
  • En que consiste la ley del emprendimiento ?
    13·1 answer
  • Discuss how you could measure Earth's diameter using nothing but a shadow-casting stick, a protractor, and a car's trip odometer
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!