Answer:
when 5% excess air is supplied, moles of air supplied/moles of fuel = 
Explanation:
Equivalence ratio = 0.6
Equivalence ratio = Actual air to fuel ratio (AAFR)/ stoichiometric air to fuel ratio SAFR
combustion reaction of propane is

From above reaction, 1 mole of propane, from the reaction, 5 moles of oxygen required,
we know that air contains 21% O_2 and 79% N_2,
Therefore, moles of air based on stoichiometry 
Theoretical air to fuel ratio 
Given
Actual Air Fuel Ratio 
when 5% excess air is supplied, moles of air supplied/moles of fuel = 
Answer:
Explanation:
Given
specific gravity of oil=0.79
height of oil column is h
height of water column is 5h
Gauge pressure at bottom is equivalent to 


Pressure due to oil and water at bottom





Answer:
(a) %RH = 45%
(b) Dp Temp = 58 °F (14.44 °C)
Explanation:
We can obtain the results easily and faster with a psychometric chart. (See the attachment). In the graph we can see how we obtain results crossing the respective data (marked in red).
First, for the relative humidity, we cross the humidity ratio (starting from the right side) with the dry temperature (horizontal axis). In that way we can read from the relative humidity curves the value of 45%.
After that, we extend the horizontal line from the right side until the left side and cross it with the 100% saturation curve in order to read the dew point temperature. Here we obtain the value 58 °F (14.44 °C)