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Radda [10]
3 years ago
13

When a user process is interrupted or causes a processor exception, the x86 hardware switches the stack pointer to a kernel stac

k, before saving the current process state. Explain why. Anderson, Thomas. Operating Systems: Principles and Practice (Volume 1 of 4) . Recursive Books. Kindle Edition.
Engineering
1 answer:
andre [41]3 years ago
7 0

Answer and Explanation

In x86, different stacks are used for kernel & user processes because of security purposes.

The kernel assigns the interrupt dispatch to a common kernel interrupt entry/exit

mechanism which saves pre-interrupt register state before summoning the registered handler(s).

When sending out an interrupt might launch a privilege and/or stack switch,

interrupts that occur while executing user process will switch to use the kernel stack in place at that point, without saving current state.

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Min is conducting an experiment where he compares the properties of water and lemonade. The first stage of the experiment is foc
madam [21]

Answer:

only if i knew

Explanation:

5 0
3 years ago
Which option identifies the next step Kristin should take to test the design in the following scenario?
Nadusha1986 [10]
The 2d sketch should be right
4 0
3 years ago
Propane burns at an equivalence ratio (ER) of 0.6, determine actual air-fuel ratio. If excess air is 5%, what will be the actual
dimaraw [331]

Answer:

when 5% excess air is supplied, moles of air supplied/moles of fuel = 23.81\times 1.05 =25

Explanation:

Equivalence ratio = 0.6

Equivalence ratio = Actual air to fuel ratio (AAFR)/ stoichiometric air to fuel ratio SAFR

combustion reaction of propane is

C_3H_8+ 5O_2 ----->3CO_2+4H_2O

From above reaction,  1 mole of propane, from the reaction, 5  moles of oxygen required,  

we know that air contains 21% O_2 and 79% N_2,

Therefore, moles of air based on stoichiometry = \frac{5}{0.21} = 23.81

Theoretical air to fuel ratio = \frac{23.81}{1} = 23.81

Given\frac{AFR}{SFR} = 0.6

Actual Air Fuel Ratio = 23.81\times 0.6 = 14.3

when 5% excess air is supplied, moles of air supplied/moles of fuel = 23.81\times 1.05 =25

6 0
3 years ago
An open tank in a petroleum company lab contains a layer of oil on top of a layer of water. The water height is 5 times the oil
maks197457 [2]

Answer:

Explanation:

Given

specific gravity of oil=0.79

height of oil column is h

height of water column is 5h

Gauge pressure at bottom is equivalent to 26.9\ mm

P_{gauge}=\rho_{Hg} gh_{Hg}

P_{gauge}=13.6\times 10^3\times 9.8\times 26.9\times 10^{-3}\ Pa

Pressure due to oil and water  at bottom

P=\rho _{oil}hg+\rho _{w}5hg

P=0.79\rho _whg+5\rho _whg=5.79\rho _{w}hg

P_{gauge}=P

13.6\times 10^3\times 9.8\times 26.9\times 10^{-3}=5.79\times 10^3\times 9.8\times h

h=63.18\ mm

6 0
3 years ago
A lecture hall having a volume of 106 ft3 contains air at 80°F, 1 atm, and a humidity ratio of 0.01 lb of water vapor per lb of
Lyrx [107]

Answer:

(a) %RH = 45%

(b) Dp Temp = 58 °F (14.44 °C)

Explanation:

We can obtain the results easily and faster with a psychometric chart. (See the attachment). In the graph we can see how we obtain results crossing the respective data (marked in red).

First, for the relative humidity, we cross the humidity ratio (starting from the right side) with the dry temperature (horizontal axis). In that way we can read from the relative humidity curves the value of 45%.

After that, we extend the horizontal line from the right side until the left side and cross it with the 100% saturation curve in order to read the dew point temperature. Here we obtain the value 58 °F (14.44 °C)

3 0
2 years ago
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