10 girls go to see a chick flick together on a friday night at their local megaplex. they buy x large popcorns and y large fount
ain drinks. together they spend $85 on snacks. they walk into an empty theater that has been recently cleaned. they have the theater to themselves. when they leave, there are 14 things in the garbage. how many large popcorns and how many large fountain drinks did they have?
1 answer:
Answer:
They had 4 large popcorn and 10 large fountain drinks
Step-by-step explanation:
The picture of the question in the attached figure
I think the price of the large popcorn is $7.50 and the price of the large fountain drink is $5.50 (The picture is not clear)
so
Let
x ----> the number large popcorns
y ----> the number of large fountain drinks
we know that
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (4,10)
see the attached figure
therefore
They had 4 large popcorn and 10 large fountain drinks
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Refer to the diagram shown below.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.