Well, the answer will depend on whether the order will count or not (based on Permutations and Combinations). <em>If the order counts</em>, then we would use the formula for Permutations, which is:

Where n is the number of items you have, and r is the number of times you choose from the items.

Which simplifies to

Which simplifies to 15*14*13 (because all the numbers 1-12 in the factorial canceled out), which gets us the answer
2730.
Now, if you wanted to find the number of ways to order the toys without replacement (<em>order doesn't count</em>), you would use the formula:

The variables are still the same, but you are now multiplying by r!.

Simplifies to

Which simplifies to (using the same cancellation method above)

Dividing 2730 by 3! will get us an answer of
455.
Really, it depends on whether they are ordered or not. In this case (since you didn't specify whether the order mattered), the answer would be
455 or
2730.
:)
the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
Answer:
See picture above
Explanation:
Hope this helps and have a nice day
Ascending order...smallest to largest
-11 - 6x + 2x^2 + 8x^3 <==
In any case. if the x values (-6) are the same for both points the equation of line would be x = -6