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marshall27 [118]
3 years ago
9

Has anyone read the book Third level

Physics
2 answers:
Bogdan [553]3 years ago
5 0
No what is it about?
dolphi86 [110]3 years ago
3 0
The Third Level by Jack Finney?
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A 20 N force is applied to an object causing it to move 10 m. How much work was done on the object? How much energy was needed t
olga2289 [7]

Answer:

Here, force=20N and displacement=10m

Work=Force×Displacement=20N×10m=200Nm

3 0
3 years ago
For an object that’s in static equilibrium which of the following statements must be true? Check all that apply.
Kobotan [32]
The statements that are held true with regards to the static equilibrium of bodies are:

<span>The net torque acting on the object must equal zero

</span><span>The net torque on the object does not have to be zero if the net force on the object is zero

Furthermore, when a body is in a state of static equilibrium, the summation of all forces, either vertically or horizontally, must be equal to zero. </span>
5 0
3 years ago
Read 2 more answers
A pendulum can be formed by tying a small object, like a tennis ball, to a string, and then connecting the other end of the stri
Usimov [2.4K]

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

<u>1- t^3</u>

<u>2- t^2</u>

<u>3- t1</u>

5 0
3 years ago
At the instant the traffic light turns green, a car that has been waiting at an intersection starts with a constant acceleration
Setler79 [48]

Answer:

(a) 300 ft

(b) 60 ft/s

Explanation:

distance d=0.5at^{2} where a is acceleration and t is time

d=0.5\times 6\times t^{2}=3t^{2}

Also, d=vt where v is the velocity

d=30t

Therefore

30t=3t^{2} hence t=10 s

Substituting t is either formula

d=30t=30*10=300 ft

Also

v=at hence v=6\times 10=60 ft/s

4 0
3 years ago
The force of repulsion between two like–charged table tennis balls is 8.2 × 10-7 newtons. If the charge on the two objects is 6.
Allisa [31]

solution

In This question we have given ,

Charge on each ball=q=6.7\times 10^{-9} C

force of repulsion between balls is F=8.2\times 10^{-7}N

Let distance between ball be x

We know by Coulombs law,

F=\frac{k\times q_{1}q_{2}}{x^2}..............(1)

here,k = 9.0\times 10^9 Nm^2C^{-2}

Put values of k and charges in equation 1

8.2\times 10^{-7}N=\frac{9.0\times 10^9 Nm^2C^{-2}\times 6.7^2\times 10^{-18} C^2}{x^2}

8.2\times 10^{-7}N\times x^2=9.0\times 10^9 Nm^2C^{-2}\times 6.7^2\times 10^{-18} C^2}

x^2=\frac{9.0\times 10^9 Nm^2C^{-2}\times 6.7^2\times 10^{-18} C^2}{8.2\times 10^{-7}N}

x=\frac{3\times 6.7}{\sqrt{820} }m

x=.701m

therefore distance between two given charges is =.701m

7 0
4 years ago
Read 2 more answers
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