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2 years ago

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Net force is the sum of all forces acting on an object. For example, in a tug of war, when one team is pulling the rope with a f

orce of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).
If both teams pull the with equal force, what would the net force be?

1 answer:

melisa1 [442]2 years ago

5 0

Answer:

If there are equal forces in both directions and there is no motion, the net force is 0 Newtons. This is because you'd be subtracting 100 from 100 which just equals 0.

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Is the relationship between velocity and centripetal force a direct, linear or nonlinear square relationship?

Svet_ta [14]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

5 0

3 years ago

A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com

bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature $=20^{\circ}C$

Final Temperature $=80^{\circ}C$

mass flow rate of cold fluid $\dot{m_c}=1.2 kg/s$

Initial Geothermal water temperature $T_h_i=160^{\circ}C$

Let final Temperature be T

mass flow rate of geothermal water $\dot{m_h}=2 kg/s$

diameter of inner wall $d_i=1.5 cm$

$U_{overall}=640 W/m^2K$

specific heat of water $c=4.18 kJ/kg-K$

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

$\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)$

$2\times (160-T)=1.2\times (80-20)$

$160-T=36$

$T=124^{\circ}C$

As heat exchanger is counter flow therefore

$\Delta T_1=160-80=80^{\circ}C$

$\Delta T_2=124-20=104^{\circ}C$

$LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}$

$LMTD=\frac{80-104}{\ln \frac{80}{104}}$

$LMTD=91.49^{\circ}C$

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

$\dot{m_c}c(80-20)=U\cdot A\cdot$ (LMTD)

$A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2$

$A=\pi DL=5.144$

$L=\frac{5.144}{\pi \times 0.015}$

$L=109.16 m$

6 0

2 years ago

How is it possible for a person watching a baseball game on TV to hear sounds before someone who is actually watching the same g

Andreyy89

Answer:

It is possible because, the TV broadcast audio and video signals in radio frequency which travels at the speed of light while the audio signals travel to those present in the stadium at the speed of sound which is over eight hundred thousand times slower than the speed of light

Explanation:

It is possible because of the following;

1. TV signals from the camera (including the captured sound) very close to the field of play are transmitted through the radio frequency bands and as such are a form of electromagnetic radiation that travels at the speed of light which is about 300,000 km/second

It will therefore, take 1 second for a sound of the game to reach someone located at 300,000,000 meters watching a live televised game

2. The speed of sound is about 343 m/second and it therefore takes up to 2 seconds for a sound to reach someone 686 meters away from the ball in the stadium.

5 0

3 years ago

PLEASE HURTY FAT ON QUIZ ATM!!!! 25 POINTS!!!!!! A student pushes a 40-N walk across the floor for a distance of 10 m how much w

algol13

Work is force times distance, so W = 40 N * 10 m = 400 J

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2 years ago

Besides adding adaptive optics to a telescope, what else can be done to reduce the effects of seeing?

anyanavicka [17]

<span>There is an low cost and quickest alternative available for adaptive optics. Name of this technique is wavefront coding. The numerical analysis pretends to show the robustness of the technique under changes in pupil diameter and wavefront shape including intersubject and intrasubject variability, using always the same restoration filter or image decoder .Using this technique it is possible to obtain high resolution images under different ocular aberrations and pupil diameters with the same decoder, opening the possibility of real time high resolution images.</span>

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2 years ago