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dusya [7]
3 years ago
8

......................

Physics
1 answer:
Ierofanga [76]3 years ago
4 0
Don’t trust those links they usually pull up your IP
You might be interested in
Blue to gray in color and reaching up to 10 feet (3.05 meters) in length and 220 pounds (99.8 kilograms) in weight, the sailfish
vagabundo [1.1K]

Answer:

the distance traveled by the fish is 3648 m

Explanation:

In general, animals have a small period of acceleration, which we will despise after which they travel at a constant speed so we can use the kinematic equations in uniform motion

   

We reduce the units to System SI

      t = 2 min (60s / 1 min) = 120 s

Calculate

       V = x / t

       x= V t

       x = 30.4 120

       x = 3648 m

 

This is the distance traveled by the fish

6 0
3 years ago
2.
gizmo_the_mogwai [7]

Answer:

a) P1=100kpa

V1=6m³

V2=?

P2=50kpa

rearranging mathematically the expression for Boyle's law

V2=(P1V1)/P2=(100×6)/50=12m³

b) same apartment as in (a) but only the value of P2 changes

=> V2=(100×6)/40=15m³

Explanation:

since temperature is not changing we use Boyle's law. mathematically expressed as P1V1=P2V2

4 0
3 years ago
A train is speeding down a railroad track at the speed of 50 miles per hour. From whose reference point is the train not moving?
marysya [2.9K]

A: a person sitting on a train

Hence person could have a meal and not get food all over them.

3 0
4 years ago
Two electric charges are moved so that they are twice as far apart as they had originally been. Is the force they experience fro
Natasha_Volkova [10]

Answer:

No.

Explanation:

The force that two particle experience is inversely proportional to the sqare of the distance, this is:

F \  \alpha \  \frac{1}{D^{2}} for a distance D

If we move them so that D is doubled:

\frac{1}{2^{2}.D^{2}  }= \frac{1}{4} \eq  \frac{1}{.D^{2}  } \eq

Then the force they experience is one fourth of the original.

5 0
3 years ago
Your companion on a train ride through Illinois notices that telephone poles near the tracks appear to be passing by very quickl
Nikitich [7]

Answer: Relative motion

Explanation: If two objects are moving either towards or away from each other with both having their velocities in a reference frame and someone is outside this reference frame seeing the motion of the two objects.

The observer ( in his own frame of reference) will measure a different velocity as opposed to the velocities of the two object in their own reference frame. p

Both the velocity measured by the observer in his own reference frame and the velocity of both object in their reference is correct.

Velocities of this nature that have varying values based on motion referenced to another body is known as relative velocity.

Motion of this nature is known as relative motion.

<em>Note that the word reference frame is simply any where the motion is occurring and the specified laws of motion is valid</em>

<em />

For this example of ours, the reference frame of the companion is the train and the telephone poles has their reference frame as the earth.

The companion will measure the velocity of the telephone poles relative to him and the velocity of the telephone pole relative to an observer outside the train will be of a different value.

6 0
3 years ago
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