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Irina18 [472]
3 years ago
6

Would adding the same number over and over again be considered a proportional relationship?

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0
No that is not a proportional relationship
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PLEASE HELP!! I WILL MARK YOU BRANLIEST! THANKS :)
Ostrovityanka [42]

Answer:

its b

Step-by-step explanation:

5 0
3 years ago
Evaluate x + 23<br> when x=7
iren2701 [21]

Answer:

30

Step-by-step explanation:

x + 23 = ?

x = 7

All we need to do is plug in x =7 to the first equation:

7 + 23 = ?

We simplify and get:

30 = ?

3 0
2 years ago
How many zeros in x^4 + 3x2 + 12
barxatty [35]

Answer:

We know that ,

Number of zeroes in a polynomial = degree of the polynomial

( degree of polynomial = the highest power in the polynomial )

therefore ,

\bold\blue{number \:of \:zeroes \:of\: the \:given} \\\bold\blue{polynomial\: = \:4}

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3 0
2 years ago
What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
3 years ago
The table shows the amounts of two ingredients Tara used to make a snack mix. She ate 5/8 cup of the snack mix for lunch. How mu
mafiozo [28]
5/8 are eaten

So if you do 8/8 - 5/8 you get 3/8
6 0
3 years ago
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