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3 years ago

15

The volume of a sphere is given by the equation =4/33, where is the radius. Calculate the volume of a sphere with a radius of 34

5 pm in cubic meters.

1 answer:

sineoko [7]3 years ago

5 0

Answer:

its 45 because of 49 og the

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Under standard-state conditions, which of the following species is the best reducing agent? a. Ag+ b. Pb c. H2 d. Ag e. Mg2+

eimsori [14]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.

$X\rightarrow X^{n+}+ne^-$

For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.

For the given options:

<u>Option a:</u> $Ag^+$

This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.

<u>Option b:</u> $Pb$

This metal can easily get oxidized to $Pb^{2+}$ ion and the standard oxidation potential for this is 0.13 V

$Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V$

<u>Option c:</u> $H_2$

This metal can easily get oxidized to $H^{+}$ ion and the standard oxidation potential for this is 0.0 V

$H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V$

<u>Option d:</u> $Ag$

This metal can easily get oxidized to $Ag^{+}$ ion and the standard oxidation potential for this is -0.80 V

$Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V$

<u>Option e:</u> $Mg^{2+}$

This ion cannot be further oxidized because +2 is the most stable oxidation state of magnesium.

By looking at the standard oxidation potential of the substances, the substance having highest positive $E^o$ potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.

From the above values, the correct answer is Option b.

8 0

3 years ago

NEED HELPPP PLSSSSSSSSSS

Leto [7]

I would pick the first option in the third option

4 0

3 years ago

QUICK 34PTS AND IF RIGHT YOU WILL GET BRAINLEST

bazaltina [42]

Answer:

1-b 2-a

Explanation:

3 0

3 years ago

The bowling ball is whizzing down the bowling lane at 4 m/s. If the mass of the bowling ball is 7 kg, what is its kinetic energy

natali 33 [55]

KE = (1/2)(m)(v^2)

KE = (1/2)(7)(4^2)

KE = (1/2)(112)

KE = 56 J

4 0

3 years ago

0.44 mL/min to microliters per second

SashulF [63]

Answer:

7 μl /s

Explanation:

Given data:

0.44 mL/min

μl /s = ?

Solution:

First of all we will convert the mL/min to mL/s.

we will divide the given value by 60.

0.44/60

0.007 mL/s

Now we will convert the mL/s to μl /s.

we will multiply the value with 1000.

0.007 × 1000

7 μl /s

7 0

3 years ago