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sammy [17]
3 years ago
6

the Hog's head pub decide to make mixture thst is 50% butterbeer. how much of an 80% butterbeer solution should mixed with 20 ga

llon of 20% butterbeer solution to create the new mixture?
Mathematics
1 answer:
evablogger [386]3 years ago
4 0
There are 20 gallons of 20% butterbeer solution.
Assume there are x gallons of 80% solution.

So total amount of the solution will be (x+20) gallons
The final solution is 50%.

So, we can set up the equation as:

0.2(20)+0.8(x)=0.5(x+20) \\ \\ 4+0.8x=0.5x+10 \\ \\ 0.8x-0.5x=10-4 \\ \\ 0.3x=6 x=20.

Thus, there will be 20 gallons of 80% butterbeer solution that is needed to be mixed with 20 gallons of 20% butterbeer solution. 

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