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3 years ago

What are the intercepts of f(x)=x^2

Mathematics

1 answer:

dusya [7]3 years ago

7 0

C. It is a basic parabola

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How to write a decimal number in two hundred ten thousand, fifty and nineteen hundredth

Vladimir [108]

Two hundred ten thousand and fifty is written as 210,050

Nineteen-hundredths is written as 19/100 or 0.19

So, the whole number is written as 210050.19

3 0

3 years ago

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Answer by today!!! x^2 + (2y) ÷ (2w) + 3z w = 2, x = 5, y = 8, z = 3

inysia [295]

Answer:

4.1

Step-by-step explanation:

5^2 + (2*8) / (2*2) + 3*3

25 + 16 / 4 + 6

41 / 10

4.1

3 0

2 years ago

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The greatest common factor of 45+9x

Tomtit [17]

9 (x + 5) the greatest common factor is 9

4 0

2 years ago

Find the unknown sizes of angles in the following figure:

8090 [49]

Answer:

angle x is 86

angle y is 38

Step-by-step explanation:

7 0

2 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

2 years ago