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raketka [301]
3 years ago
8

Arrange the elements in decreasing order of first ionization energy.

Chemistry
1 answer:
just olya [345]3 years ago
5 0

Answer:

The decreasing order of first ionization energy: Se > Ge > In > Cs

The decreasing order of first ionization energy: x > y > z

Explanation:

Ionization energy refers to the energy needed to completely pull out an electron from the valence shell of a neutral gaseous atom.

First ionization energy is the energy involved in the removal of first valence electron.

<u><em>In the periodic table, down the group, as atomic radius of elements increases, the ionization energy decreases </em></u>

<u><em>Whereas, across a period, as atomic radius of elements decreases, the ionization energy increases.</em></u>

PART (A):

Position of the given elements in the periodic table:

Indium (In): Group 13, period 5

Germanium (Ge): Group 14, period 4

Selenium (Se): Group 16, period 4

Caesium (Cs): Group 1, period 6

Thus, the increasing order of atomic radius: Se < Ge < In < Cs

<u>Therefore, the decreasing order of first ionization energy: </u><u>Se > Ge > In > Cs</u>

PART (B):

Given elements:

element x: radius = 110 pm

element y: radius = 199 pm

element z: radius = 257 pm

Thus, the increasing order of atomic radius: x < y < z

<u>Therefore, the decreasing order of first ionization energy:</u><u> x > y > z</u>

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Explanation:

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Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>

So, you must just convert the given temperature, 32°F, to kelvin scale.

You can do that in two stages.

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Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K

Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.

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