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raketka [301]
3 years ago
8

Arrange the elements in decreasing order of first ionization energy.

Chemistry
1 answer:
just olya [345]3 years ago
5 0

Answer:

The decreasing order of first ionization energy: Se > Ge > In > Cs

The decreasing order of first ionization energy: x > y > z

Explanation:

Ionization energy refers to the energy needed to completely pull out an electron from the valence shell of a neutral gaseous atom.

First ionization energy is the energy involved in the removal of first valence electron.

<u><em>In the periodic table, down the group, as atomic radius of elements increases, the ionization energy decreases </em></u>

<u><em>Whereas, across a period, as atomic radius of elements decreases, the ionization energy increases.</em></u>

PART (A):

Position of the given elements in the periodic table:

Indium (In): Group 13, period 5

Germanium (Ge): Group 14, period 4

Selenium (Se): Group 16, period 4

Caesium (Cs): Group 1, period 6

Thus, the increasing order of atomic radius: Se < Ge < In < Cs

<u>Therefore, the decreasing order of first ionization energy: </u><u>Se > Ge > In > Cs</u>

PART (B):

Given elements:

element x: radius = 110 pm

element y: radius = 199 pm

element z: radius = 257 pm

Thus, the increasing order of atomic radius: x < y < z

<u>Therefore, the decreasing order of first ionization energy:</u><u> x > y > z</u>

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