For the 52nd electron must pair with one of the electrons in the 5p orbital.
1 answer:
Answer:
This question is incomplete
Explanation:
This question is incomplete, however, the element that has 52 electrons only is Tellurium (Te) and when the electronic configuration of elements with more than 52 electrons are written, the 52nd electron is indicated/paired the same way the 52nd electron of Te is indicated/paired. Hence, while writing the electronic configuration of Te, it is written as
[Kr] 4d¹⁰ 5s² 5p⁴ where [Kr] is the electronic configuration of krypton. Based on this, we can deduce that the 52nd electron will be in the first orbital of the P subshell (as attached in the picture). This is because when indicating the electrons in the subshell, one electron will be spread across each orbital and if any electron is still remaining, it will be added starting from to the first orbital of the subshell, however no two electrons in an orbital in a subshell can have the same spin and hence must face opposite direction based on pauli's exclusion principle (as seen in attached); thus for the 5p-orbital of elements with 52 or more electrons, when one electron each is represented in each box (3 boxes in total) in the 5p-orbital, the remaining electron is paired with the the first electron in the first box of the 5p-orbital
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Answer:
- <em>The relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volume measurements is</em> that <u>the larger the divisions the larger the uncertainty, and the smaller the divisions the smaller the uncertaintity.</u>
Explanation:
In general, <em>graduated cylinders</em> are marked with divisions (lines) at equal spaces or intervals. There are divisions that show the measure with a number and a series of intermediate not numbered divisions in between two numbered lines.
The <em>uncertainty </em>of the instrument is determined as half the difference between two consecutive marks.
So, the larger the interval of two consecutive marks the larger the uncertainty.
The attached image, taken from brainly.com/question/13102373, shows you some marks in a graduated cylinder.
Answer:
15.9 g
Explanation:
(Take the atomic mass of C=12.0, H=1.0, O=16.0)
no. of moles = mass / molar mass
no. of moles of octane used = 11.2 / (12.0x8 + 1x18)
= 0.0982456 mol
Since oxygen is in excess and octane is the limiting reagent, the no. of moles of H2O depends on the no. of moles of octane used.
From the balanced equation, the mole ratio of octane : water = 2:18 = 1: 9,
so this means, one mole of octane produced 9 moles of water.
Using this ratio, we can deduce that (y is the no. of moles of water produced):
y = 0.0982456x9
y= 0.88421 mol
Since mass = no. of moles x molar mass,
mass of water produced = 0.88421 x (1.0x2+16.0)
=15.9 g