Answer:
The brightness of a line depends on the number of electrons making that transition.
Explanation:
In atomic spectra, some electronic transitions are “forbidden” by the rules of quantum mechanics. That is, <em>some transitions are less probable than others</em>.
The brightness of a given line depends on the number of electrons making that transition.
Allowed transitions will give the brightest lines. The brightness of the other lines will vary depending on how likely the transitions are.
Answer:
The vapor pressure at 60.21°C is 327 mmHg.
Explanation:
Given the vapor pressure of ethanol at 34.90°C is 102 mmHg.
We need to find vapor pressure at 60.21°C.
The Clausius-Clapeyron equation is often used to find the vapor pressure of pure liquid.
We have given in the question
And is the Universal Gas Constant.
Taking inverse log both side we get,
Since 1.00 atm is equal to 760 mmHg, the height of the column of mercury which would create pressure equal to 1.00 atm is 760 mm or 76 cm
<h3>What are the units of pressure?</h3>
Pressure is defined as the force acting perpendicularly per unit area of a surface.
The units of pressure include;
- millimetres of mercury, mmHg
- aatmospheres, atm,
- pascals, Pa
- Newtons per square metre, N/m^2
1 atmosphere is equal to 760 mmHg.
Therefore, the height of the column of mercury which would create pressure equal to 1.00 atm is 760 mm or 76 cm
Learn more about pressure at: brainly.com/question/25934121
Answer:
Mass = 15600 g
Explanation:
Given data:
Number of atoms of oxygen = 5.87 × 10²⁶
Mass of oxygen = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
5.87 × 10²⁶ atom × 1 mole / 6.022 × 10²³ atom
0.975 × 10³ mole
975 mole
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 975 × 16 g/mol
Mass = 15600 g
Dimensional analysis:
5.87 × 10²⁶ atom × 1 mol/6.022 × 10²³ atom × 16 g/ 1 mol = 15600 g
Answer:
Explanation:
Ksp(BaSO4)=1.07×10−10
BaSO₄ → Ba²⁺ + SO₄²⁻
1.07×10⁻¹⁰ = ( Ba²⁺) × ( SO₄²⁻)
but Ba²⁺ = 1.3×10⁻² M
1.07×10⁻¹⁰ = 1.3×10⁻² M × ( SO₄²⁻)
( SO₄²⁻) = 1.07×10⁻¹⁰ / 1.3×10⁻² = 0.823 × 10⁻⁸ M
while Ksp(CaSO4)=7.10×10−5
CaSO₄ → Ca²⁺ + SO₄²⁻
7.10×10⁻⁵ = 2.0×10⁻² × ( SO₄²⁻)
( SO₄²⁻) = 7.10×10⁻⁵ / 2.0×10⁻² = 3.55 × 10⁻³ M
comparing the concentration of sulfate ions, Ba²⁺ cation will precipitate first because the Ba²⁺ requires 0.823 × 10⁻⁸ M sodium sulfate which less compared the about needed by CaSO₄