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Alona [7]
4 years ago
13

For the oxidation of glucose C6 H12 O6 + 602 -- 6H2O + 6C02, How many moles of oxygen will it take to consume 3.9 moles of gluco

se C6 H12 O6?
27
.12
.65
23.4
Chemistry
1 answer:
Mamont248 [21]4 years ago
5 0

Answer:

The answer to your question is 23.4 moles of Glucose

Explanation:

Data

moles of Oxygen = ?

moles of glucose = 3.9

-Balanced chemical reaction

           1C₆H₁₂O₆  +  6O₂   ⇒   6H₂O  +  6CO₂

Process

1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.

           1 mol of C₆H₁₂O₆ -------------------- 6 moles of O₂

    3.9 moles of C₆H₁₂O₆ ------------------   x

                                  x = (3.9 x 6 ) / 1

                                  x = 23.4 moles

2.- Conclusion

3.9 moles of glucose consume 23.4 moles of oxygen

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Calculate the pH during the titration of 20.00 mL of 0.1000 M dimethylamine, (CH3)2NH(aq), with 0.1000 M HCl(aq) after 21.23 mL
Evgesh-ka [11]

The pH value of the solution is mathematically given as

pH=2.35

<h3>What pH value of the solution?</h3>

Question Parameters:

pH during the titration of 20.00 mL of 0.1000 M dimethylamine,

with 0.1000 M HCl(aq) after 21.23 mL of the acid

Generally, the equation for the  Chemical Reaction  is mathematically given as

(CH3)2NH(aq), +Hcl   ---> <---- (CH3)2NH2Cl(aq)

Therefore

HCl=\frac{0.186mol}{41.86}

HCL=0.00444M

WHere

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Hence

H+=0.00444M

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pH=log(0.00444)

pH=2.35

For more information on Chemical Reaction

brainly.com/question/11231920

8 0
2 years ago
Write a full set of quantum numbers for the following:
Troyanec [42]

Explanation:

It is known that the maximum value of ml is equal to the vale of l. But the minimum value of n is as follows.

                    n = l + 1

where,     n = principle quantum number  

                l = azimuthal quantum number

Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l is 0 for s, 1 for p, 2 for d, 3 for f, and so on.

Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.

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5 0
3 years ago
Rank and explain how the freezing point of 0.100 m solutions of the following ionic electrolytes compare. List from lowest freez
Elden [556K]

Answer:

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Explanation:

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Formula is:

ΔT = Kf . m . i

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Kf is the cryoscopic constant

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In this case, T° freezing pure solvent is 0° because it's water, so the Kf is 1.86 °C/m, and m is 0.1 molal.

The i modifies the T° freezing solution. The four salts, are ionic compounds, so for each case:

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KBr →  K⁺  +  Br⁻   i = 2

Solution of Mg₃(PO₄)₂ will have the lowest temperature of freezing and the solution of KBr, the highest (always lower, than 0°).

8 0
3 years ago
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