Answer:
0.382g
Explanation:
Step 1: Write the reduction half-reaction
Al³⁺(aq) + 3 e⁻ ⇒ Al(s)
Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s
We will use the following relationships.
- 1 mole of electrons has a charge of 96486 C (Faraday's constant)
- 1 mole of Al is produced when 3 moles of electrons pass through the cell.
- The molar mass of Al is 26.98 g/mol.
The mass of Al produced is:
Answer:
The flow rate would be 22.5ml/hr
Explanation:
Volumetric flow rate = Mass flow rate ÷ density
Mass flow rate = 3mg/min = 3mg/min × 60min/1hr = 180mg/hr
Density = mass/volume = 2g/250ml = 0.008g/ml = 0.008g/ml × 1000mg/1g = 8mg/ml
Volumetric flow rate = 180mg/hr ÷ 8mg/ml = 22.5ml/hr
Signs that a chemical reaction is occurring are: 1. change in color 2. change in odor 3. change in pH, as in changes from acid to base or base to acid
Answer:
28.01g
Explanation:
Given the weight of one mole of Cabon as 12.01g and that of oxygen as 16.00g.
The molecular weight of a compound can be gotten by adding the molar weights of the elements that constitutes the compound .
The molecular weight of the compound CO is therefore
equal to the sum of the weight of both elements.
That’s = 12.01g + 16.00g
= 28.01g
Therefore, the molecular weight of CO is 28.01g
