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dangina [55]
3 years ago
10

during the spin dry cycle of a washing machine, the motor slows from 90 rad/s to 30 rad/s while turning the drum though an angle

of 180 radians. what is the magnitude of the angular acceleration of the motor?a 64 rad/s^2b 32 radc 10 radd 20 rade 1.0 rad
Physics
1 answer:
Doss [256]3 years ago
5 0

Answer:

option D

Explanation:

given,

initial speed of motor, ω₁ = 90 rad/s

final speed of motor, ω₂ = 30 rad/s

angle, θ = 180 rad

angular acceleration,α = ?

using equation of rotational motion

 ω₂² = ω₁ ² + 2 α θ

  90² = 30² + 2 x α x 180

     360 α = 7200

     α = 20 rad/s²

the angular acceleration of the motor comes out to  be 20 rad/s²

the correct answer is option D

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Plz i need help for the 5 problems. plz show the work!!!
Artemon [7]

Answer:

1.   3 m/s^{2}

2.   1.5 m/s^{2}

3.   3 seconds

4.   0 m/s^{2}

5.   2.2 seconds

Explanation:

(1)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

Substituting u=0 since it’s at rest, v=30m/s and t=10 seconds

a = \frac {30-0}{10}=3 m/s^{2}

(2)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

Substituting u=10m/s, v=22m/s and t=8 seconds

a = \frac {22-10}{8}=1.5 m/s^{2}

(3)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making t the subject we have

t=\frac {v-u}{a}

Substituting u=0m/s since at rest, v=15m/s and a=5 \frac {m}{s^{2}}

= \frac {15-0}{5}=3s

(4)

When initial and final velocity are constant, there’s no acceleration as proven below

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

Substituting u=20 since it’s at rest, v=20m/s and t=10 seconds

a = \frac {20-20}{10}=0 m/s^{2}

(5)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making t the subject we have

t=\frac {v-u}{a}

Substituting u=9m/s since at rest, v=0m/s and a=-4.1 \frac {m}{s^{2}}

= \frac {0-9}{-4.1}=2.2s

8 0
3 years ago
The distance between the centers of the wheels of a motorcycle is 146 cm. The center of mass ofthe motorcycle, including the rid
Vitek1552 [10]

Answer:

9.12267515924 m/s²

Explanation:

Here the moment created by the wheels and the moment created by the center of gravity will balance each other.

h = Height of the center of mass = 78.5 cm

d =  Distance from back wheel to the center of mass = \dfrac{146\times 10^{-2}}{2}\ m

g = Acceleration due to gravity = 9.81 m/s²

a = Horizontal acceleration

The equation is of the form

mgd=Fh\\\Rightarrow mgd=mah\\\Rightarrow a=\dfrac{gd}{h}\\\Rightarrow a=\dfrac{9.81\times \dfrac{146\times 10^{-2}}{2}}{78.5\times 10^{-2}}\\\Rightarrow a=9.12267515924\ m/s^2

The horizontal acceleration of the motorcycle that will make the front wheel rise off the ground is 9.12267515924 m/s²

8 0
3 years ago
An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi
MAXImum [283]

Answer:

The answer is I=70,513kgm^2

Explanation:

Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.

When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius

Now we will find the Moment of Inertia this way:

Ft*r=I*a -> (Ft*r)/(a) = I

Replacing we get that I is:

I=(200N*0,33m)/(0,936rad/s^2)

Then I=70,513kgm^2

In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:  

I=(1/2)*(m*r^2)

4 0
3 years ago
A motorcycle of mass 100 kilograms travels around a flat, circular track of radius 10 meters with a constant speed of 20 meters
JulijaS [17]

Answer:

100/10 = 10 , 10 × 10 = 100÷20 = 5

I'm pretty sure its wrong

8 0
3 years ago
Read 2 more answers
A 2-kg bowling ball sits on top of a building that is 40 meters tall.
Dahasolnce [82]
The bowling ball is at rest, so it only has gravitational potential energy.

Ug = mgy
Ug = (2)(9.8)(40) = 784 J

Need any more help?
6 0
3 years ago
Read 2 more answers
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