(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)
Answer:
Explanation:
For this we're going to use conservation of mechanical energy because there are nor dissipative forces as friction. So, the change on mechanical energy (E) should be zero, that means:
(1)
With 
the initial kinetic energy, 
the initial potential energy, 
the final kinetic energy and 
the final potential energy. Note that initialy the masses are at rest so 
, when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so 
. So, equation (1) becomes:
(2)
At initial moment all the potential energy is gravitational because the spring is not stretched so 
and at final moment we have potential gravitational energy and potential elastic energy so 
, using this on (2)
(3)
Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), 
and we have by (3) :
(4)
Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:
dividing both sides by d
, with k the constant of the spring and g the gravitational acceleration.
Answer:
1.19cm^3 of glycerine
Explanation:
Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:
Volume of spill glycerine = change in volume of glycerine - change in volume of aluminum
Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature
coefficient of volume expansion of aluminum = coefficient of linear expansion of aluminum*3 = 23*10^-6 * 3 = 0.69*10^-4 oC^-1
Change in temperature = 41-23 = 18oC
Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3
C. Forces have mass and take up space
Choice ' C ' is a true statement.
The other choices aren't.
