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gtnhenbr [62]
3 years ago
6

Why does the volume of water in a cylinder increase when it is heated

Physics
1 answer:
Contact [7]3 years ago
6 0
Heat causes the water molecules to move faster. As the molecules move apart, the water has a greater volume and less density.
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How are evaporation and transpiration similar?
Iteru [2.4K]
The answer is A. They are both processes in which water is changed into water vapor.
7 0
3 years ago
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A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
pav-90 [236]

Answer

given,

current (I) = 16 mA

circumference of the circular loop (S)= 1.90 m

Magnetic field (B)= 0.790 T

S = 2 π r

1.9 = 2 π r

r = 0.3024 m

a) magnetic moment of loop

    M= I A

    M=16 \times 10^{-3} \times \pi \times r^2

   M=16 \times 10^{-3} \times \pi \times 0.3024^2

   M=4.59 \times 10^{-3}\ A m^2

b)  torque exerted in the loop

 \tau = M\ B

 \tau = 4.59 \times 10^{-3}\times 0.79

 \tau = 3.63 \times 10^{-3} N.m

8 0
3 years ago
How do you find the direction of displacement?
andreyandreev [35.5K]
You draw a straight line from the start point to the end point. It doesn't matter what route was actually followed for the trip.
3 0
3 years ago
Suppose you lived in a pre-industrial society and needed to lift a heavy (20 kg) block a height of 5 m and had two choices for h
igomit [66]
Let's break the question into two parts:

1) The force needed in Ramp scenario.
2) The effort force needed in the lever scenario.

1. Ramp Scenario: 
In an incline, the only component of cart's weight(mg) that is in the direction of motion is mgsin \alpha. Therefore the effort force in this case must be equal or greater than mgsin \alpha.

Now we need to find \alpha. \alpha is the angle between the incline of the ramp and the ground. 

Since the height is 5m and the length of the ramp is 8m, sin \alpha would be 5/8 or 0.625. Now that you have sin \alpha, mutiple it with mg.

=> m*g*sin \alpha  = 20 * 10 * 5 / 8. (Taking g = 10 m/s² for simplicity) = 125N
Therefore, the minimum Effort force you would require in this case is 125N.

2. Lever Scenario:
Just apply "moment action" in this case, which is:
F_{e}  d_{e}  = F_{r}  d_{r}

F_{e} = ?

F_{r} = mg = 20 * 10 = 200N
d_{e} = 10m
d_{r} = 1m


Plug-in the values in the above equation:
F_{e} = 200/10= 20N


As 20N << 125N, the best choice is to use lever.

4 0
3 years ago
Sophie throws a tennis ball down from a height of 1.5 m at an angle of 450 with respect to vertical. She drops another tennis ba
Katena32 [7]

Given that,

Height =1.5 m

Angle = 45°

We need to find the greater speed of the ball

Using conservation of energy

P.E_{i}+K.E_{f}=P.E_{f}+K.E_{f}

mgh+\dfrac{1}{2}mv_{i}^2=mgh+\dfrac{1}{2}mv_{f}^2

Here, initial velocity and final potential energy is zero.

mgh=\dfrac{1}{2}mv_{f}^2

Put the value into the formula

9.8\times1.5=\dfrac{1}{2}v_{f}^2

v_{f}^2=2\times9.8\times1.5

v_{f}=\sqrt{2\times9.8\times1.5}

v_{f}=5.42\ m/s

Hence, the greater speed of the ball is 5.42 m/s.

5 0
3 years ago
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