All categories

2 years ago

Explain why the reactivity series must be used for single replacement reactions, but not for double replacement.

Chemistry

1 answer:

Anarel [89]2 years ago

4 0

Answer:

Here's what I get

Explanation:

In a single replacement reaction, one element must displace another element from its compound.

Thus, we must consider the reactivity series, because an element lower down in the series cannot replace one that is above it.

In a double replacement reaction, the cations change partners with the anions. All we need consider are the solubilities of the new cation-anion partners.

You might be interested in

A sample of nitrogen gas occupies 1.55 L at

34kurt

Answer:

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

1.55 L / 300 K = V2 / 173 K

V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

The new volume after the temperature reduced to -100 °C is 0.894 L

3 0

2 years ago

A compound with the empirical formula CH2 was found to have a molar mass of approximately 112 g. Write the molecular formula of

san4es73 [151]

Answer:

C8H10

Explanation:

n (CH2) = 112

n (12 + 1 + 1) = 112

n (14) = 112

n = 8

Molecular Formula: C8H10

6 0

2 years ago

______ reactions release energy.

Igoryamba

Combustion reactions release energy in the form of heat.
Hope this helps and tell me if you need more help!

4 0

3 years ago

PLS HELP ASAP WITH THIS SCIENCE HW

natta225 [31]

Answer:

Convex mirrors are more study than flat mirrors.

Explanation:

This is the correct answer because i have already studied this

6 0

2 years ago

A buffer solution is composed of 1.00 mol of acid and 2.25 mol of the conjugate base. If the p K a of the acid is 4.90 , what is

Gemiola [76]

<u>Answer:</u> The pH of the buffer is 5.25

<u>Explanation:</u>

Let the volume of buffer solution be V

We know that:

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution}}$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjugate base}]}{[acid]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of weak acid = 4.90

$[\text{conjugate base}]=\frac{2.25}{V}$

$[acid]=\frac{1.00}{V}$

pH = ?

Putting values in above equation, we get:

$pH=4.90+\log(\frac{2.25/V}{1.00/V})\\\\pH=5.25$

Hence, the pH of the buffer is 5.25

4 0

2 years ago