Hi there!
We can find the perimeter of a rectangle by using the following formula:
perimeter = 2 × width + 2 × length
In the question, we are given the following data: the length of the rectangle is 12 in and the perimeter is 56. Let's substitute this into our formula!
56 = 2 × width + 2 × 12
Multiply first.
56 = 2 × width + 24
Now subtract 24 from both sides.
32 = 2 × width
And finally, to find the width of the rectangle, divide both sides of the equation by 2.
16 = width
(we can eventually switch sides in the equation).
width = 16
~ Hope this helps you!
Answer:
(0.084,0.396)
Step-by-step explanation:
The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as
By rounding to three decimal places we get,
The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).
9514 1404 393
Answer:
- non-leap years: 31/365
- leap years: 31/366
Step-by-step explanation:
As a fraction of the number of days in a calendar year, it will depend on whether the year is a leap year.
non-leap years have 365 days, so 31 days is 31/365 years.
leap years have 366 days, so 31 days is 31/366 years.
_____
If you're asking for the purpose of computing interest, you need to be aware that "ordinary interest" counts 360 days in a year. 31 days would be 31/360 years. "Exact interest" counts 365 days in a year, so 31 days would be 31/365 years.
In astronomy, the definitions of "day" and "year" may vary, depending on the frame of reference and what direction in space marks the boundary of the period. The precise fraction will depend on how you define these terms and where the clock is located.
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
