Question

A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume is 7.70 L, and the final pressure is 1.25 atm, what was the initial temperature of the krypton?

Answer 1

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas  = 7.70 litres

final pressure of the Krypton gas  = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the  Combined Gas Laws:

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Rearranging the equation:

T1  = $\frac{P1V1T2}{P2V2}$

Putting the value in the equation:

T1 = $\frac{0.960 X 6 X 323.15}{1.25 X 7.70}$

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K