Pls click on the photo and answer both questions Pls Answer ASAP :-)

20 PTS!

mafiozo [28]

Answer:

finding the number of equal-sized parts into which a number can be split

Step-by-step explanation:

Let us split the number 80 into 10 equal parts.

80 = 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8

= 8 + 8 + 8 +...to 10 times

= 8(10)

or $\frac{80}{10} =8$

So, if N is any number and p is one of its equal part, then the number of parts into which N is split by p is $\frac{N}{p}$ .

Hence, finding the number of equal-sized parts is best modeled with a division expression.

4 0

4 years ago

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Find the value of x (click photo)

Zolol [24]

Answer:

x = 130 degrees

Step-by-step explanation:

7-sided polygon = 900 degrees

114 + 138 + 127 + 108 + 142 + 141 + x = 900

770 + x = 900

-770 -770

x = 130

Hope this helped! Have a nice day! Plz mark as brainliest!!!

-XxDeathshotxX

5 0

3 years ago

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If sin(x) = squareroot 2 over 2 what is cos(x) and tan(x)

Bumek [7]

Answer:

cos(x) = square root 2 over 2; tan(x) = 1

Step-by-step explanation:

$\frac{\sqrt{2} }{2}$

was, before it was rationalized,

$\frac{1}{\sqrt{2} }$

Therefore,

$sin(x)=\frac{1}{\sqrt{2} }$

The side opposite the reference angle measures 1, the hypotenuse measures square root 2. That makes the reference angle a 45 degree angle. From there we can determine that the side adjacent to the reference angle also has a measure of 1. Therefore,

$cos(x)=\frac{1}{\sqrt{2} }=\frac{\sqrt{2} }{2}$ and

since tangent is side opposite (1) over side adjacent (1),

tan(x) = 1

7 0

3 years ago

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

$\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]$

The left and right endpoints of the $i$ -th subinterval, respectively, are

$\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8$

$r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8$

for $1\le i\le4$ , and the respective midpoints are

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8$

Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

$T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}$

Midpoint rule

We approximate the area for each subinterval by

$M_i=f(m_i)(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}$

Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial $p_i(x)$ , where

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It so happens that the integral of $p_i(x)$ reduces nicely to the form you're probably more familiar with,

$S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))$

Then the integral is approximately

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}$

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0

3 years ago

A recipe for 48 cookies use 2 and 2/3 cups of biscuit mix how many cookies are made from each cup of cookies

madreJ [45]

Answer:

i believe the answer is B

Step-by-step explanation:

make 2 and 2/3 a decimal

2 divided by 3 will give you .6 repeating. just round to .8

then divide 48 by 2.8

it will give you 17.142

i just rounded it to 18... bc its so close to it

hope this helps :)

5 0

3 years ago

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