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trasher [3.6K]
3 years ago
15

What is the force required to lift the balloon with

Physics
1 answer:
Olin [163]3 years ago
3 0

No force is required to lift that balloon. In fact, force is required to hold it down, and if you let go, it's up, up, and away.

Since the balloon's density is less than the density of the air around it, it's lighter than the air it displaces, there is a net upward buoyant force acting on it, and it floats up !

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You release a block from the top of a long, slippery inclined plane of length l that makes an angle θ with the horizontal. The m
Mars2501 [29]

Answer:

potential enrgy   U = m g L sin θ

speed     V = √(2g L sin θ)

Explanation:

The expression for the gravitational potential energy of a body is

                    U = mg Y - mg Yo

Where Y give us a constant initial energy from which the differences are measured, for general simplicity it is selected as zero, Yo= 0

What we find an expression for height, let's use trigonometry

                       sin  θ= Y / L

                       Y = l sin θ

   We substitute in the power energy equation

                     U = m g L sin θ

                         

2. The mechanical energy of the system is conserved, so we will write the mechanical energy at two points the highest and the lowest

Highest           Em = U

Lower              Em = K

                         U = K

                         m g L sin θ = ½ m v²

                         V = √(2g L sin θ)

4 0
3 years ago
A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts
Tresset [83]

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

3 0
3 years ago
. Mass 1 has a momentum of 20 kg*m/s. Mass 2 has a momentum of 50 kg*m/s.
sesenic [268]

Answer:

55kgm/s

Explanation:

3 0
3 years ago
You have probably noticed that carrying a person in a pool of water is much easier than carrying a person through air. To unders
Kruka [31]

Answer:

The answer is "0.91238 and 744.8"

Explanation:

In this scenario it is easier to take a person to the water-pool than to transport the people in the air, as the person's strength is increased by water upwards:

f_b \to m \to mg =person \\\\F_B \ in\  air = v\ & air\  g \\\\

               =0.076 \times 1.225 \times 9.8 \\\\ =0.91238 \ N\\\\

F_B \ in \ water = v  \& water \ g \\\\

                    =0.076 \times 1000 \times 9.8\\\\= 744.8 \ N\\

6 0
2 years ago
What is the net force acting on the buggy. ?The net force is pointing to the ?
Papessa [141]

Answer: 390, right

explanation: The net force is just the sum of all of these forces acting on an object. ... This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula.

6 0
3 years ago
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