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trasher [3.6K]
3 years ago
15

What is the force required to lift the balloon with

Physics
1 answer:
Olin [163]3 years ago
3 0

No force is required to lift that balloon. In fact, force is required to hold it down, and if you let go, it's up, up, and away.

Since the balloon's density is less than the density of the air around it, it's lighter than the air it displaces, there is a net upward buoyant force acting on it, and it floats up !

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What is the mass of a liquid having a density of 1.50 g/ml and a volume of 3.5 liters?
PIT_PIT [208]

We know the formula for density = Mass/ volume

So     Mass, M = Volume * Density

         Volume = 3.5 L= 0.0035m^3

         Density = 1.50 g/ml  = 1500 kg/m^3

         Mass, M =  0.0035*1500 = 5.25 kg

So mass of liquid having density 1.50 g/ml and volume 3.5 liters is 5.25 kg.

6 0
3 years ago
A 357 kg box is pulled 8.00 m up a 30° frictionless, inclined plane by an external force of 4925 N that acts parallel to the pla
Sidana [21]
I'm so tremble right now
4 0
3 years ago
In order for an object to have kinetic energy it must have a mass and a ?
almond37 [142]

Answer:

Velocity

Explanation:

  • The mechanical energy of the body is defined as the sum of the potential energy and kinetic energy.

                                   E = P.E + K.E

  • The potential energy of a body is due to the height from the surface of the earth.

                                  P.E = mgh

  • The kinetic energy of the is possessed by the body due to the virtue of its motion,

                                  K.E = ½ mv²

  • If there is no velocity associated with the body, there is no K.E in the body.
8 0
3 years ago
Light bulb 1 operates with a filament temperature of 2700 K whereas light bulb 2 has a filament temperature of 2100 K. Both fila
Lemur [1.5K]

Answer:

0.3659

Explanation:

The power (p) is given as:

P = AeσT⁴

where,

A =Area

e = transmittivity

σ = Stefan-boltzmann constant

T = Temperature

since both the bulbs radiate same power

P₁ = P₂

Where, 1 denotes the bulb 1

2 denotes the bulb 2

thus,

A₁e₁σT₁⁴ = A₂e₂σT₂⁴

Now e₁=e₂

⇒A₁T₁⁴ = A₂T₂⁴

or

\frac{A_1}{A_2} =\frac{T_{2}^{4}}{T_{1}^{4}}

substituting the values in the above question we get

\frac{A_1}{A_2} =\frac{2100_{2}^{4}}{2700_{1}^{4}}

or

\frac{A_1}{A_2} }=0.3659

6 0
3 years ago
Tessa wonders how many different ways she can light a lightbulb. Circle all the ways you think will work.
adell [148]
It’s just E because ethe positiv and negative current are supposed to flow thorough the bulb in opppsote sides at a equel level.In some them negerive/postive is absent and some of them are connected to the same side
4 0
2 years ago
Read 2 more answers
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