Because your taking a educated guess on what will happened if the track member drinks the energy drink
Respuesta: verifique amablemente la explicación
Explicación:
Dado lo siguiente:
Longitud (L) del cable = 120 m
Diámetro (d) = 2,2 mm (2,2 / 1000) = 2,2 * 10 ^ -3 m
Fuerza (F) = 380 N
Esfuerzo longitudinal = Fuerza / Área
Área = πd² / 4 = (π * (2.2 * 10 ^ -3) ^ 2) / 4
Área = (3.142 * 4.84 * 10 ^ -6)
Área = 0.00000380132 m²
Estrés = Fuerza / Área
Estrés = 380 / 0.00000380132
Esfuerzo longitudinal = 99952128.12 = 9.9952128 * 10^7 Nm^-2
Deformación longitudinal: extensión / longitud
Extensión = 0.10 m
Longitud = 120 m
Deformación longitudinal = 0,1 m / 120 m
Deformación longitudinal = 0.0008333 = 8.33 × 10 ^ -4
The answer is Convoluted endoplasmic reticulum
1. 12.75 J
Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is
where
F = 15 N is the magnitude of the force
d = 85 cm = 0.85 m is the displacement of the cart
Substituting in the formula, we get
2. 10.6 N
In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).
Therefore, the work done is
However, in this case the displacement is
d = 120 cm = 1.20 m
Therefore, the magnitude of the force in this case is
Answer is 6 tires.
This is a projectile question.
First make sure units are consistent - express speed in m/s.
20 km/h = 20000m / 3600 s = 5.56 m/s
Assume the takeoff point of the ramp is at ground level (height, h, = 0m). We need to determine how long Joe is in the air, and use that time to calculate the horizontal distance he traveled.
Joe is traveling 5.56 m/s on a ramp angled at 20 degrees. There are vertical and horizontal components to his speed:
Vertical speed = 5.56sin20 = 1.90 m/s
Horizontal speed = 5.56cos20 = 5.22 m/s
An easy way to proceed is to calculate the time it takes for Joe’s vertical speed to reach 0m/s - this represents the time when Joe is at his maximum height and is therefore halfway through the trip. Double whatever time this is to find the total time of the trip. Remember he is decelerating due to gravity:
Time to peak:
a = Δv / Δt
-9.8 = -1.9 / Δt
Δt = 0.19s
Total trip time:
0.19 x 2 = 0.38s
Now that we have the total tome Joe is in the air, we can find the horizontal distance he traveled:
v = d / t
5.22 = d / 0.38
d = 1.98m
Now divide this total distance by the length of an individual tire to find the number of tires he will clear:
1.98 / 0.3 = 6.6 tires
Therefore he can jump 6 tires safely (he will land in the middle of the 7th tire).
Lots of steps I know but just try to think of the situation and keep track of the vertical and horizontal things!
