Answer:
Explanation:
Given
Motorcyclist speed=12 m/s
maximum acceleration
distance=39 m
Let x be the distance traveled by motorist in his reaction time
therefore remaining 39-x will be traveled with
acceleration

s=39-x
v=0
u=12 m/s

x=27 m
Therefore he traveled 27 m in his reaction time

t=2.25 s
(b)If his reaction time is 2.56 sec
then distance traveled in his reaction time

Remaining distance 39-30.72=8.28 m
therefore its velocity when it reaches the deer


v=6.681 m/s
I believe that the statement is true. <span>Investigations allow for the control of variables. Changing variables will lead you to observations that may prove your hypothesis. Hope this answers the question. Have a nice day. Please feel free to ask more questions.</span>
Assume that the small-massed particle is
and the heavier mass particle is
.
Now, by momentum conservation and energy conservation:


Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

So now, we see that
and
. So therefore, the smaller mass recoils out.
Hope this helps you!
Bye!
Answer:
Gravity? is it multiple choice?