Increased lamp voltage is achieved by turning the light intensity dial.
To enlarge the diameter of the hole and let more light through the slide, the iris diaphragm was modified.
Condenser: Position it higher and closer to the slide's bottom to better direct light to the centre of the slide.
<h3>
How do you adjust the light level on a microscope?</h3>
Utilize the brightness adjustment knob to change the brightness. Turn the brightness control knob while looking through the eyepieces to make sure there is no glare in the field of view.
Use a daylight balancing filter if your compound microscope has a certain sort of illumination. It typically rests directly on top of the luminator or in a filter holder above the light. This filter is blue.
The daylight balancing filter will correct the colour temperature and produce a higher-quality image if your microscope is lighted by tungsten or halogen (and a better colour image). This blue filter is not necessary if your microscope is an LED.
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The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and m₂ will be u₁=5 and u₂=0 m/s respectively,
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
m₁u₁+m₂u₂=(m₁+m₂)v
M×5+3M×0=[M+3M]v
The final velocity is found as;
V=51.25 m/s
The velocity of block A is found as;
Hence, the final velocity of the block A will be 2.5 m/sec.
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Answer:
Explanation:
r = Radius = 2.7 cm
F = Force = 
A = Area = 
= Stress = 
E = Young's modulus = 
= Strain
= Original length = 67 cm
= Change in length
Young's modulus is given by
Strain is
Strain is given by
The cylinder height decreases by
Answer:
The solution set of a disjunction is the union of the solution sets of the individual inequalities. A convenient way to graph a disjunction is to graph each individual inequality above the number line, then move them both onto the actual number line
Explanation:
