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aleksklad [387]
3 years ago
8

What is a system of equations for the following situation? A group of 14 people went to see a movie. The cost to go to the movie

is $12 for an adult and $8 for a child. The total cost for the group was $144.
Mathematics
2 answers:
SashulF [63]3 years ago
7 0

Answer:

144=12x+8y

x+y=14

Step-by-step explanation:

algol [13]3 years ago
4 0

Answer:

12x + 8 (14 - x ) = $ 144

x + (14-x) = 14

Step-by-step explanation:

Total number of people = 14

Let the number of adults be x and the number of children be ( 14 - x)

Total cost for the group = $144

i.e., 12x + 8 ( 14-x) = 144

12x + 112 - 8x = 144

4x + 112 = 144

4x = 144-112

4x = 32

x = 32/4

x = 8

Number of adults = x = 8

Number of children = 14 - x = 14 - 8 = 6

Hope it helps : )

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the volume of a triangular prism is 42 cubic centimeters. what is the volume of a similar prism that is twice as large as large
Dmitriy789 [7]

Answer:

The volume of the similar prism is 336\ cm^{3}

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x----> the volume of the larger prism

y----> the volume of the smaller prism

so

z^{3}=\frac{x}{y}

In this problem we have

z=2 -----> the scale factor

y=42\ cm^{3}

substitute and solve for x

x=42(2^{3})=336\ cm^{3}

3 0
3 years ago
Compute 860 times 500
mr_godi [17]

Answer:430,000

Step-by-step explanation:

Type it into your calculator and you get that number

8 0
3 years ago
This is a 3 part question, PLEASE HELP ILL GIVE BRAINLY
kaheart [24]

Answer:

Angle of A = 90 degree-62 degree =  28 degree.

Step-by-step explanation:

tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319

cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47  = 5.3 / 0.47  = 11.3

or another way.

sin (62) = 10 /c  ---> c = 10/ sin (62) = 10 / 0.88 = 11.3

So Angle of A = 28 degree.

a = 5. 3

c =  11.3.

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7 0
3 years ago
What is the square root of 36x to the fourth power?
-BARSIC- [3]
\sqrt{36x^4}=\sqrt{36}\cdot\sqrt{x^4}=\sqrt{6^2}\cdot\sqrt{(x^2)^2}=6\cdot x^2=\boxed{6x^2}
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The reflection of a Quadrant II point is located in Quadrant I. Assuming no error was made, what kind of reflection occurred?
gizmo_the_mogwai [7]

Answer:

A reflection across the y- axis

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y) → (-x, y)

A point in the second quadrant (- x, y)

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3 0
3 years ago
Read 2 more answers
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