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REY [17]
3 years ago
15

Solve the proportion 35/30 = 28/? A. 48 B. 23 C. 24 D. 46

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

C. 24

Step-by-step explanation:

by algebra:

let "?" be x

35/30 = 28 / x   (multiply both sides by 30)

35 = (28/x) (30)   (multiply both sides by x)

35x = (28)(30)

35x = 840  (divide both sides by 35)

x = 840 / 35

x = 24

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34.
poizon [28]

Answer:

The lateral surface area of the triangular prism is 379.5sq units

Step-by-step explanation:

The side lengths of the base of the triangular prism are 5 meters, 8 meters, and 10 meters.

It is given that the height of the prism is 16.5 meters.

To determine the lateral surface area of the prism, let us use the formula  

where a, b,c are the side lengths of the base of the triangular prism and h is the height of the prism.

Here  and  

Substituting these values in the formula, we have,

Simplifying, we get,

Multiplying, we get,

Thus, the lateral surface area of the triangular prism is

6 0
3 years ago
Read 2 more answers
Will give brainliest! which of the following correctly shows the beginning steps to solve this equation?
padilas [110]
2(7x - 3) = 9

step 1 : distribute thru the parenthesis......14x - 6 = 9
step 2 : add 6 to both sides.......14x = 15
7 0
3 years ago
X + 25 = 96. Solve for x.
Jobisdone [24]

Answer:

x = 71

Step-by-step explanation:

x + 25 = 96

=> x = 96 - 25

=> x = 71

4 0
2 years ago
Read 2 more answers
An ion channel can be in either open (O) or closed (C) states. If it is open, then it has probability 0.1 of closing in 1 micros
iragen [17]

Answer:

a)  P (COO)  = 0,135

b) P ( SISI) = 0,00015

Step-by-step explanation:

a) the probability of an ion channel in open position is 50 %   0,5

   the probability of an ion channel in close position is 50 %   0,5

probability for the following sequence of states COO

to be closed   0,5    (C)

from (C) to pass to open  0,3  (O)

and to stay O  is 0,9

Then the probability of the sequence of states COO is

P (COO)  = 0,5 * 0,3 * 0,9  

P (COO)  = 0,135

b) If people are either infected or susceptible, then

Probability of an individual infected is  0,5

Probability of an individual susceptible  is 0,5

to pass from susceptible to infected is 0,05

to pass from infected to susceptible is 0,12

then

P ( SISI) = 0,5 * 0,05*0,12*0,05

P ( SISI) = 0,00015

probability for the following sequence of states COO

4 0
3 years ago
Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?
dusya [7]
\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\

\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}

\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )
7 0
3 years ago
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