Answer:
The program is given below with appropriate comments for better understanding
Explanation:
#Program
# foot stride = 2.5 feet
# 1 mile = 5280 feet
no_stride_first_min = int(input('Enter the number strides made durng the first minute of jogging: '))
no_stride_last_min = int(input('Enter the number strides made durng the last minute of jogging: '))
avg_stride_one_min = (no_stride_first_min + no_stride_last_min)/2 # calculates the average stride per minute
jogging_duration = float(input('Enter the total time spent jogging in hours and minute: '))
jogging_duration_hours = int(jogging_duration) # gets the hour
jogging_duration_min = jogging_duration - int(jogging_duration) # gets the minute
tot_jogging_duration_min = jogging_duration_hours*60 + jogging_duration_min # calculates total time in minutes
dist_feet = (avg_stride_one_min*2.5)*tot_jogging_duration_min # calculates the total distance in feet
dist_miles = dist_feet/5280 # calculates the total distance in mile
print('Distance traveled in miles = {0:.2f} miles'.format(dist_miles))
Answer:
-Differential equation: d²T/dx² = 0
-The boundary conditions are;
1) Heat flux at bottom;
-KAdT(0)/dx = ηq_e
2) Heat flux at top surface;
-KdT(L)/dx = h(T(L) - T(water))
Explanation:
To solve this question, let's work with the following assumptions that we are given;
- Heat transfer is steady and one dimensional
- Thermal conductivity is constant.
- No heat generation exists in the medium
- The top surface which is at x = L will be subjected to convection while the bottom surface which is at x = 0 will be subjected to uniform heat flux.
Will all those assumptions given, the differential equation can be expressed as; d²T/dx² = 0
Now the boundary conditions are;
1) Heat flux at bottom;
q(at x = 0) is;
-KAdT(0)/dx = ηq_e
2) Heat flux at top surface;
q(at x = L):
-KdT(L)/dx = h(T(L) - T(water))
Explanation:
<u>Ohmic Behavior:</u>
If the current "I" produced in a conductor due to voltage "V" applied across it, is directly proportional to that voltage while the resistance of the conductor is same/constant, the material is said to be ohmic material or possessing ohmic behavior. If the resistance of a conductor doesn't remain the same due to heat, material property or any other reason, non-ohmic behavior will be observed.
<u>Thermal Expansion vs Ohmic/Non-ohmic property:</u>
For a linear conductor, thermal expansion (may be due to heat produced in result of current flow) increases length of the material due to which its resistance increases directly. Whenever the resistance increases during the flow of a current, the non-ohmic behavior arises.
R = ρL/A
where,
R=Resistance of conductor
ρ=Resistivity of material
L=length of conductor
A=Cross-sectional area of the conductor.
But,
usually this change in length and consequently change is resistance is very minor, so ignoring this change, the non-ohmic property of material will be minor too.
<u>Non-Ohmic Property:</u>
Current flows in a conductor due to flow of electrons in it. When these flowing electrons interacts with other particles (electron or atoms' nucleus) heat is produced. Due to this heat, atomic particles vibrates with more speed resulting in more hindrance/resistance in the flow of electron i.e. Resistance of material is now increased, so this will result in Non-ohmic behavior because now for the same value of applied voltage V, the flow of electron (Current) will be lesser. This will result in deviation from straight line graph as well (picture is attached)
Answer:
The voltage input to the inverting terminal is 60μV
Explanation:
Given;
open-loop gain, A = 150,000
output voltage, V₀ = 15 V
voltage at the inverting input, = −40 μV = 40 x 10⁻⁶ V
The relationship between output voltage and voltage at the inverting input is given as;
Therefore, the voltage input to the inverting terminal is 60μV
Answer:
1.80 m
Mezzanine floors shall have a clear ceiling height of not less than 1.80 m above and below it.
Explanation:
Hope it helps