1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisov135 [29]
4 years ago
11

Can thermal expansion explain the non-ohmic behavior? If not, describe what happens at the atomic level that accounts for the no

n-ohmic property.

Engineering
1 answer:
wel4 years ago
6 0

Explanation:

<u>Ohmic Behavior:</u>

If the current "I" produced in a conductor due to voltage "V" applied across it, is directly proportional to that voltage while the resistance of the conductor is same/constant, the material is said to be ohmic material or possessing ohmic behavior. If the resistance of a conductor doesn't remain the same due to heat, material property or any other reason, non-ohmic behavior will be observed.

<u>Thermal Expansion vs Ohmic/Non-ohmic property:</u>

For a linear conductor, thermal expansion (may be due to heat produced in result of current flow) increases length of the material due to which its resistance increases directly. Whenever the resistance increases during the flow of a current, the non-ohmic behavior arises.

R = ρL/A

where,

R=Resistance of conductor

ρ=Resistivity of material

L=length of conductor

A=Cross-sectional area of the conductor.

But,

usually this change in length and consequently change is resistance is very minor, so ignoring this change, the non-ohmic property of material will be minor too.

<u>Non-Ohmic Property:</u>

Current flows in a conductor due to flow of electrons in it. When these flowing electrons interacts with other particles (electron or atoms' nucleus) heat is produced. Due to this heat, atomic particles vibrates with more speed resulting in more hindrance/resistance in the flow of electron i.e. Resistance of material is now increased, so this will result in Non-ohmic behavior because now for the same value of applied voltage V, the flow of electron (Current) will be lesser. This will result in deviation from straight line graph as well (picture is attached)

You might be interested in
How many squares titles (20cm x 20cm) are needed to coat the sides and base of a pool which is 10m long, 6 meter wide and 3m dee
Zanzabum

Answer:

3900 tiles

Explanation:

7 0
3 years ago
A piston-cylinder device contains 0.15 kg of air initially at 2 MPa and 350 °C. The air is first expanded isothermally to 500 kP
Semmy [17]

Answer:

Isothermal  expansion W₁ =-37198.9 J

Polytropic Compression W₂ =-34872.82 J

Isobaric Compression W₃ =  -6974.566 J

The net work for the cycle = -79046.29 J

Explanation:

Mass of air = 0.15 kg = 150 g

Molar mass = 28.9647 g/mol

Number of moles = 150 g /28.9647 g/mol = 5.179 moles of air

PV = nRT therefrore V = nRT/(P) = 5.179*8.314*(350+273.15)/(2×10⁶) = 0.0134167 m³

For isothermal expansion we have

P₁V₁ = P₂V₂ or V₂ = P₁V₁/P₂ = 2×10⁶*0.0134167 / (5×10⁵) = 0.0536668 m³

Therefore work done

W₁ = -nRTln(V₂/V₁) = -26833ln(4) = -37198.9 J

Stage 2

Compression polytropically we have

\frac{P_2}{P_3} = (\frac{V_3}{V_2} )^n  where P₃ = 2 MPa

Therefore V₃ = (\frac{1}{4} )^{\frac{1}{1.2} }*V_2  = 1.6904×10⁻² m³

Work = W₂ = \frac{P_2V_2-P_3V_3}{n-1} =  -34872.82 J

\frac{P_2}{P_3} = (\frac{T_2}{T_3} )^\frac{n}{n-1}     or T₃ = T_2*(\frac{P_3}{P_2})^\frac{n-1}{n} = 785.12 K

Isobaric compression we have  thus

Work done W₃ = P(V₁ -V₃) = -6974.566 J

Total work = W₁ + W₂ + W₃ = -37198.9 J + -34872.82 J + -6974.566 J = -79046.29 J

7 0
3 years ago
An empty metal can is heated to 908C and sealed. It is then placed in a room to cool to 208C. What is the pressure inside the ca
Natali5045456 [20]

The pressure inside the can upon cooling is 0.4 atm.

<u>Explanation:</u>

Given -

Initial Temperature, T1 = 908°C = 908 + 273 K = 1181 K

Final Temperature, T2 = 208°C = 208 + 273 K = 481 K

Pressure upon cooling, P2 = ?

Using Gay Lussac's law:

P1/T1 = P2/T2

P2 = P1 X T2 / T1

P2 = 1 atm X 481 / 1181

P2 = 0.4 atm

Therefore, the pressure inside the can upon cooling is 0.4 atm.

3 0
3 years ago
A. 50
Licemer1 [7]

Answer:

love

Explanation: you

5 0
3 years ago
Someone please please help me and explain!! I will give brainliest if right!!!
Mariulka [41]

R=10+15+30

55 is the answer to the question

5 0
3 years ago
Read 2 more answers
Other questions:
  • The density of oxygen contained in a tank is 2.0 kg/m3 when the temperature is 25 °C. Determine the gage pressure of the gas if
    12·1 answer
  • A rod of length L lies along the x axis with its left end at the origin. It has a nonuniform charge density λ = αx, where α is a
    14·2 answers
  • DO NOW: Name the three main legal categories of ownership.
    12·1 answer
  • n open feedwater heater operates at steady state with liquid water entering inlet 1 at 10 bar, 50°C. A separate stream of steam
    8·1 answer
  • So far in your lifetime, about how much garbage have you contributed
    12·1 answer
  • In an apartment the interior air temperature is 20°C and exterior air temperatures is 5°C. The wall has inner and outer surface
    8·1 answer
  • Why are Gas cars Bad?(cons) give me reasons why gasoline cars are bad<br><br>Thx if u help ​
    14·1 answer
  • A front wheel drive vehicle with four wheel disc brakes is pulling to the left. Tech A says an external kink or internal restric
    13·1 answer
  • There are three homes being built, each with an identical deck on the back. Each deck is comprised of two separate areas. One ar
    7·1 answer
  • How many hours should I charge a 4.8 volt 600mah battery(it is urgent)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!