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3 years ago

14

NASA SPACE SHUTTLE QUESTION:

1 answer:

vfiekz [6]3 years ago

8 0

Explanation:

The Challenger accident made them aware of the risks. They had been a little naive, since it was never believed that such a thing could happen. This, together with Space Shuttle Columbia disaster revealed the risks of the space shuttle program, which also had very high maintenance costs.

You might be interested in

Don't break or crush mercury-containing lamps because mercury powder may be released.

alexandr402 [8]

A.

It would be released without a doubt so be careful!

Hope this helps :)

5 0

4 years ago

Guys, I need help. Describe carburetion as it applies to the four-stroke engine.

marta [7]

Answer:

(NH4)2Cr2O7→Cr2O3+N2+4H2O

Explanation:

(NH4)2Cr2O7→Cr2O3+N2+4H2O

7 0

3 years ago

A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted

polet [3.4K]

Answer:

HV = 372.4 KGf/mm^2

$HR_C = 39.445$

Explanation:

given data:

minimum tensile strength = 1240 MPa

we knwo that $\sigma_{vrs}$ and brinell hardness number (HB} relation given as

$\sigma_{vrs} = 3.4 \times H.B$

$H.B = \frac{1240}{3.4} = 364.7$

1) relation betwen H.B and Rockwell is

$HR_C = 6.96 + 0.089 HB$

$HR_C = 6.96 + (0.089\times 365} = 39.445$

2) relation between HB and Vickers hardnes HV is given as

$HB \times 1.05 = HV + 10.5$

$HV = HB\times 1.05 - 10.5$

HV = 372.4 KGf/mm^2

4 0

4 years ago

Other examples of joption

Evgen [1.6K]

Answer:

Profit from stock price gains with limited risk and lower cost than buying the stock outright.

Profit from stock price drops with limited risk and lower cost than shorting the stock.

Profit from sideways markets by selling options and generating income.

Get paid to buy stock.

Explanation:

I don’t know if you meant option but I hope this helps.

7 0

3 years ago

a. Replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs can save a lot of energy. Cal

monitta

Answer:

a) 1512000 Joules

b) 5040 seconds = 84 minutes = 1.4 hours

Explanation:

a) Power saved by replacing bulbs = 60-18 = 42 W = 42 J/s

Time the bulb is used for = 10 hours

Energy saved during this time

42×10×60×60 = 1512000 Joules

Saved energy by replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs in 10 hours is 1512000 Joules

b) Power the plasma TV uses = 300 W = J/s

$\frac{1512000}{300}=5040\ s$

Time a plasma TV can be used for with the saved energy is 5040 seconds = 84 minutes = 1.4 hours.

4 0

3 years ago