Answer:
(a) The speed of the target proton after the collision is:
, and (b) the speed of the projectile proton after the collision is: 
.
Explanation:
We need to apply at the system the conservation of the linear momentum on both directions x and y, and we get for the x axle:
, and y axle:
. Now replacing the value given as: 
, 
for the projectile proton and according to the problem 
are perpendicular so 
, and assuming that 
, we get for x axle:
and y axle: 
, then solving for 
, we get:
and replacing at the first equation we get:
, now solving for 
, we can find the speed of the projectile proton after the collision as: and 
, that is the speed of the target proton after the collision.
Answer:
Sugar can’t enter cells directly
Explanation:
So when blood sugar level rises, cells in the pancreas signal for the release of insulin into the bloodstream. The insulin attaches to the sugars and signals cells to let it enter with the attached sugar. Insulin is known as the key that unlocks cells.
I hope I helped
Answer:
1. 3 m
2. 27 s
Explanation:
1. "A car traveling at +33 m/s sees a red light and has to stop. If the driver can accelerate at -5.5 m/s², how far does it travel?"
Given:
v₀ = 33 m/s
v = 0 m/s
a = -5.5 m/s²
Unknown: Δx
To determine the equation you need, look for which variable you don't have and aren't solving for. In this case, we aren't given time and aren't solving for time. So look for an equation that doesn't have t in it.
Equation: v² = v₀² + 2aΔx
Substitute and solve:
(0 m/s)² = (33 m/s)² + 2(-5.5 m/s²) Δx
Δx = 3 m
2. "A plane starting from rest at one end of a runway accelerates at 4.8 m/s² for 1800 m. How long did it take to accelerate?"
Given:
v₀ = 0 m/s
a = 4.8 m/s²
Δx = 1800 m
Unknown: t
Equation: Δx = v₀ t + ½ a t²
Substitute and solve:
1800 m = (0 m/s) t + ½ (4.8 m/s²) t²
t ≈ 27 s
