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3 years ago

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What is Stefan's botmann's constant

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

The Stefan–Boltzmann constant (also Stefan's constant), a physical constant denoted by the Greek letter σ (sigma), is the constant of proportionality in the Stefan–Boltzmann law: "the total intensity radiated over all wavelengths increases as the temperature increases", of a black body which is proportional to the ...

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Why is a control group important?

Likurg_2 [28]

Answer:

A. It changes all the time, allowing us to see if the experimental group stays the same.

control group mean the thing the stay the same during the Experiment.

I hope this help

I hope this is correct

4 0

4 years ago

A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 6.0 m, y = 10.0 m, and has vel

mihalych1998 [28]

Explanation:

Given that,

Position of the particle at t = 0,

$y=(6i+10j)\ m$

Velocity of the particle at t = 0

$u=(1i+6j)\ m$

Acceleration of the particle,

$a=(5i+7j)\ m/s^2$

Solution,

(a) Let v is the velocity at t = 10 s. Using the equation of kinematics as :

$v=u+at$

$v=(1i+6j)+(5i+7j)10$

$v=(51i+76j)\ m/s$

(b) Let y' is the position at t = 1 s. Again using second equation of kinematics as :

$y'=y+ut+\dfrac{1}{2}at^2$

$y'=(6i+10j)+(1i+6j)1+\dfrac{1}{2}\times (5i+7j)1^2$

$y'=\dfrac{19}{2}i+\dfrac{39}{2}j$

(c) Magnitude of y',

$|y'|=\sqrt{(\dfrac{19}{2})^2+(\dfrac{39}{2})^2}$

|y'| = 21.69 meters

Direction of the y',

$tan\theta=\dfrac{y}{x}$

$tan\theta=\dfrac{39/2}{19/2}$

$\theta=64.02^{\circ}$

Hence, this is the required solution.

4 0

3 years ago

What state of matter has the most energy

fredd [130]

Answer:

gas particles have the greatest amount of energy

6 0

3 years ago

Heat transfer between two substances is affected by specific heat and the

Pie

<span>Heat transfer between two substances is affected by specific heat and the "Temperature difference between them"

Hope this helps!</span>

6 0

3 years ago

Read 2 more answers

A cyclist rides 6.2 km east, then 9.28 km in a direction 27.27 degrees west of north, then 7.99 km west. A. What is the magnitud

Pani-rosa [81]

Answer:

Explanation:

given,

cyclist ride 6.2 km east and then 9.28 km in the direction of 27.27° west of north and then 7.99 km west.

vertical component = 9.28 cos∅

= 9.28 cos 27.27°

= 8.24 km

horizontal axis component = 9.28 sin ∅

= 9.28 sin 27.27°

= 4.5 km

distance of the final point from the origin

= 7.99 -(6.2-4.5)

= 6.29 km

displacement

$d = \sqrt{6.29^2+8.24^2}$

d = 10.37 km

b) $tan \theta = \dfrac{6.29}{8.24}$

θ = 37.36°

4 0

3 years ago