Answer:
20 J/g
Explanation:
In this question, we are required to determine the latent heat of vaporization
- To answer the question, we need to ask ourselves the questions:
What is latent heat of vaporization?
- It is the amount of heat required to change a substance from its liquid state to gaseous state without change in temperature.
- It is the amount of heat absorbed by a substance as it boils.
How do we calculate the latent heat of vaporization?
- Latent heat is calculated by dividing the amount of heat absorbed by the mass of the substance.
In this case;
- Mass of the substance = 20 g
- Heat absorbed as the substance boils is 400 J (1000 J - 600 J)
Thus,
Latent heat of vaporization = Quantity of Heat ÷ Mass
= 400 Joules ÷ 20 g
= 20 J/g
Thus, the latent heat of vaporization is 20 J/g
Answer:
This is false.
Explanation:
Heat rash develops when some of your sweat ducts clog. Instead of evaporating, perspiration gets trapped beneath the skin, causing inflammation and rash. Heat rash is usually self-limited, meaning it resolves on its own without treatment. Over-the-counter treatments such as calamine, hydrocortisone cream, itch preparations (such as Benadryl spray), or sunburn lotions can be used as skincare to treat the itching and burning symptoms. Heat rash usually goes away on its own within three or four days so long as you don't irritate the site further. Heat rash happens when the sweat glands get blocked. The trapped sweat irritates the skin and leads to small bumps.
Answer:
a) > x<-c(1,2,3,4,5)
> y<-c(1.9,3.5,3.7,5.1,6)
> linearmodel<-lm(y~x)
And the output is given by:
> linearmodel
Call:
lm(formula = y ~ x)
Coefficients:
(Intercept) x
1.10 0.98
b) 
And if we compare this with the general model 
We see that the slope is m= 0.98 and the intercept b = 1.10
Explanation:
Part a
For this case we have the following data:
x: 1,2,3,4,5
y: 1.9,3.5,3.7,5.1, 6
For this case we can use the following R code:
> x<-c(1,2,3,4,5)
> y<-c(1.9,3.5,3.7,5.1,6)
> linearmodel<-lm(y~x)
And the output is given by:
> linearmodel
Call:
lm(formula = y ~ x)
Coefficients:
(Intercept) x
1.10 0.98
Part b
For this case we have the following trend equation given:
And if we compare this with the general model
We see that the slope is m= 0.98 and the intercept b = 1.10
Answer:
all of those are pisitions
Explanation:
Answer:
true?
Explanation:
Im positive but not 100% sure wait for someone else to answer and see if they say the same.
