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Answer:
K.E is 2.25 J
Explanation:
Data :
Mass = m = 0.5 kg
Velocity = v = 3 m/s
Formula for K.E
K.E = 1/2mv²
Put values
K.E = 1/2(0.5)(3)² = 2.25 J
Explanation:
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Answer:
The work done by the catcher is 120 J.
Explanation:
Given;
velocity of the fastball, v = 40 m/s
mass of the fastball, m = 150 g = 0.15 kg
Based on work-energy theorem, the work done by the catcher is equal to the kinetic energy of the fastball.
The kinetic energy of the fastball is given as;
K.E = ¹/₂mv²
K.E = ¹/₂ x 0.15 x 40²
K.E = 120 J
Therefore, the work done by the catcher is 120 J.