Question

Chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium chloride solution. Be sure your answer has the correct number of significant digits

Answer 1

Answer: The concentration of barium chloride is $3.0\times 10^1\mu M$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Let us assume:

Moles of barium chloride = $8.9\mu mol$

Volume of flask = 300 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{8.9\mu mol\times 1000}{300mL}=3.0\times 10^1\mu M$

Hence, the concentration of barium chloride is $3.0\times 10^1\mu M$