Answer:
Explanation:
<u>1) Data:</u>
a) Hypochlorous acid = HClO
b) [HClO} = 0.015
c) pH = 4.64
d) pKa = ?
<u>2) Strategy:</u>
With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.
<u>3) Solution:</u>
a) pH
b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)
c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]
d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M
e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M
f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46
Answer: 17.9 g
Explanation:
1) Chemical equation:
H₂ (g) + Cl₂ (g) → 2HCl (g)
2) mole ratios:
1 mol H₂ : 1 mol Cl₂ : 2 mol HCl
3) Since, the pressure and temperature conditions do not change, the same proportion is valid for the volumes. Then:
1 liter H₂ / 2 liter HCl = 5.15 liter H₂ / x
⇒ x = 5.5 × 2 / 1 = 11 liter HCl
4) Calculate the number of moles of HCl in 11 liter of HCl at STP
At STP, 1 mol of gas = 22.4 liter
⇒ 11 liter × 1mol / 22.4 liter = 0.491 mol HCl
5) Use the molar mass to convert 0.491 mol to grams
molar mass of HCl = 1.008 g/mol + 35.453 g/mol = 36.461 g/mol
mass in grams = nuumber of moles × molar mass = 36.461 g/mol × 0.491 mol = 17.90 g.
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Answer:
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Explanation:
I can't understand your language sorry .
