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Mariana [72]
3 years ago
15

Khalad is measuring the amplitude of a wave. What can be known about this wave?

Chemistry
2 answers:
lorasvet [3.4K]3 years ago
6 0
B.It is a transverse wave
nadya68 [22]3 years ago
6 0
B is the correct answer hope this helps
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Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels select
Schach [20]

This question is incomplete, the complete question is;

Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels selectively permeable only to chloride ions. The left compartment (also called inside) contains 1 mM Cl- and the right compartment (also called outside) contains 100 mM Cl-. What will the electrical potential be when the system attains equilibrium? [ assume body temperature; log 100 = 2, log 10 = 1, log 1 = 0, log 0.1 = -1, log 0.01 = -2]

Options;

a) -62 mV

b) -124 mV

c) +62 mV

d) 0 mV

e) +124 mV

Answer:

the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

Explanation:

Given the data in the question;

Two compartments are divided by lipid bilayer;

In inside compartment Cl- ion concentration- 1mM and out side of the cell concentration is 100mM

now we apply the Nernst equilibrium potential equation;

Chlorine ion valency is z = –1

So

E_{eq} = 62/z × log(ion outside/ ion inside) [for Cl‐ ions]

E_{eq} = (62 / –1) x log(  100 / 1 )

 E_{eq} = -62 x 2 =

E_{eq}  = –124mV

Therefore, the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

4 0
3 years ago
An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of
RSB [31]

Answer:

V=0.0310L=3.10mL

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

n_{acid}=n_{KOH}

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL

Best regards!

7 0
3 years ago
Which equation is derived from the combined gas law?
Aloiza [94]

Answer:

The correct answer is V1/T1=V2/T2.

Explanation:

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5 0
3 years ago
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What happens to the air particles when air expands?
rjkz [21]

All the particles gain more energy and move quicker and therefore they spread out causing air to expand

3 0
3 years ago
What type of energy does a cup sitting on a table have? Why?
Sedbober [7]

Answer:

POTENTIAL ENERGY

A cup sitting on a table possesses potential energy

Explanation:

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5 0
3 years ago
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