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Scorpion4ik [409]

3 years ago

14

Which type of lens will produce a virtual image

1 answer:

Naily [24]3 years ago

7 0

When a object is close to the converging lens it behaves like a magnifying glass. Therefore convex mirror produces a virtual image. A real image occurs when a ray converges, whereas virtual image occurs when rays only Appear to converge.

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Which element does not contain any neutrons ?

wolverine [178]

Hydrogen does not contain any neutrons

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3 years ago

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At what location in this diagram do the magnetic field lines show that the magnetic field is strongest ?

34kurt

Answer: A or D I'd think D

Explanation: we're c is located the lines are all belong pulled towards the southern pole of the magnet while we're A is located it s between both poles.

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3 years ago

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A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a

Verizon [17]

Answer:

The shear deformation is $\Delta x=3.34\times10^{-6}\ m$ .

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus $S = 1\times10^{9}\ N/m^2$

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

$S=\dfrac{Fl_{0}}{A\Delta x}$

$\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}$

$\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}$

Put the value into the formula

$\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}$

$\Delta x=3.34\times10^{-6}\ m$

Hence, The shear deformation is $\Delta x=3.34\times10^{-6}\ m$ .

7 0

3 years ago

What does a photovoltaic cell do?

Pie

Answer:

last option

Explanation:

photovoltaic cell is when the sun's energy will be converted to as electricity causing an effect to create light for houses

8 0

3 years ago

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You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

4 years ago