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Daniel [21]
3 years ago
12

A student is transmitting sound waves through various materials. Through which metal in the table will the sound waves travel th

e fastest? Aluminum Copper Lead Brass (70% Cu, 30% Zn) 6,420 4,700 5,010 1,960 Speed of sound (m/s) O
A. Brass O
B. Aluminum
C. Copper O
D. Lead​
Physics
2 answers:
SashulF [63]3 years ago
7 0

Answer:aluminum

Explanation:

MariettaO [177]3 years ago
5 0

Answer:

Aluminum

Explanation:

promise

give  me brainlest plleaseee

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Which property of metals allows corrosion to take place? reactivity malleability ductility conductivity Description
horrorfan [7]
Your best bet would be reactivity
7 0
3 years ago
Read 2 more answers
The equivalent resistance of a series combination of resistors is always greater than any individual resistance
Likurg_2 [28]

Answer:

true

Explanation:

Series resistors are additive

r1 + r2 + r3 = r total    the total will always be greater than any one of the parts

8 0
2 years ago
Suppose that the dipole moment associated with an iron atom of an iron bar is 2.8 × 10-23 J/T. Assume that all the atoms in the
masya89 [10]

To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.

The diple moment associated with an iron bar is given by,

\mu = \alpha *N

Where,

\alpha = Dipole momento associated with an Atom

N = Number of atoms

\alpha y previously given in the problem and its value is 2.8*10^{-23}J/T

L = 5.8cm = 5.8*10^{-2}m

A = 1.5cm^2 = 1.5*10^{-4}m^2

The number of the atoms N, can be calculated as,

N = \frac{\rho AL}{M_{mass}}*A_n

Where

\rho = Density

M_{mass} = Molar Mass

A = Area

L = Length

A_n =Avogadro number

N = \frac{(7.9g/cm^3)(1.5cm)(5.8cm^2)}{55.9g/mol}(6.022*10^{23}atoms/mol)

N = 7.4041*10^{23}atoms

Then applying the equation about the dipole moment associated with an iron bar we have,

\mu = \alpha *N

\mu = (2.8*10^{-23})*(7.4041*10^{23})

\mu = 20.72Am^2

PART B) With the dipole moment we can now calculate the Torque in the system, which is

\tau = \mu B sin(90)

\tau = (20.72)(2.2)

\tau = 45.584N.m

<em>Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.</em>

3 0
3 years ago
The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th
FrozenT [24]

0.74in

Explanation:

Given parameters:

length range of adult mosquito = 3.0 - 6.0mm

Smallest mosquito = 2.5mm

Largest mosquito = 19mm

Average mass range = 3.0 - 5.0mg

Unknown:

Length of largest known mosquito in inches = ?

Solution;

The length is the longest dimension. It is how long a body is.

 The problem here is converting from mm to inches;

 

The length of the longest mosquito which is the largest is 19mm

 19mm to inches;

     1mm = 0.039inches

  19mm = 19mm x \frac{0.039in}{1mm} = 0.74in

learn more:

Scale brainly.com/question/570757

#learnwithBrainly

4 0
3 years ago
If this decay has a half-life of 10.2 years, what mass of 60.8g carbon-14 will remain after 20.4 years
OLEGan [10]
20.4 years is 20.4/10.2 = 2 half-life cycles, which means a quarter of the starting mass or 15.2 g will remain after this time.
5 0
3 years ago
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