Answer:
Explanation:
Given
Distance putty has to travel is 3.5 m
The initial speed of putty is 9.50 m/s
Using equation of motion to determine the velocity of putty just before it hits ceiling
So, the velocity of putty just before hitting is
When the course deviation indicator (CDI) needle is centered during an omnireceiver check using a VOR test signal (VOT), the omn
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Answer:
the coefficient of volume expansion of the glass is
Explanation:
Given that:
Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³
temperature of the glass flask and mercury= 1.00° C
After heat is applied ; the final temperature = 52.00° C
Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C
Volume of the mercury overflow = 8.50 cm^3 = 8.50 × 10⁻⁶ m³
the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K
The increase in the volume of the mercury = 10⁻³ m³ × 51.00 × 1.80 × 10⁻⁴
The increase in the volume of the mercury =
Increase in volume of the glass = 10⁻³ × 51.00 ×
Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask
the mercury overflow =
Thus; the coefficient of volume expansion of the glass is
Answer:
denisity = 52.33 g/c
Explanation:
Density:
We have that m = 785 and that v = 15 c.
d = 52.33