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Mrac [35]
3 years ago
14

For 1981, 1987, and 1990, how does the frequency of left-mouthed breeding adults compare to the frequency of left-mouthed indivi

duals in the entire population?
Biology
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

The variation might occur in the population that leads to the evolution of the species. This variation may occur due to natural selection, mutation or recombination.

The variation might change the genotype and allelic frequency of the population and might also change the phenotype of the individual in the population. The breeding adults of the left mouthed in 1981, 1987 and 1990 shows variation and was equally opposite phenotype which is more common in the population.

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3 years ago
You cross two true-breeding parents (one with yellow seeds and one with green seeds), grow and self-pollinate the F1 generation,
Andru [333]

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1500

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Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.

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Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500

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