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Vlad [161]
3 years ago
14

The price that a company charged for a basketball hoop is given by the equation 50-5x^2 where x is the number of hoops that are

produced, in millions. It costs the company $30 to make each basketball hoop. The company recently reduced its production to 1 million hoops but maintained its profit of 15 million dollars. Approximately how many basketball hoops did the company previously produce to make the same profit?
Mathematics
2 answers:
jasenka [17]3 years ago
5 0

Answer:

The company produced 2 million  basketball hoops in previous year.

Step-by-step explanation:

Let the number of basketball hoops produced by the company be x.

The equation of price is  

P=50-5x^2

The cost of each basketball hoop is $30, so the cost function is

C=30x

The profit function is the difference between price and cost function.

Profit=P(x)-C(x)

Profit=50-5x^2-30x

The company reduced its production to 1 million hoops and make profit of 15 million.

15=50-5(x-1)^2-30(x-1)

15=50-5(x^2-2x+1)-30x+30

15=50-5x^2+10x-5-30x+30

5x^2+20x-60=0

5(x^2+4x-12)=0

(x^2+6x-2x-12)=0

(x+6)(x-2)=0

Therefore value of x is -6 and 2. The production can not be negative, therefore the company produced 2 million  basketball hoops in previous year.

Debora [2.8K]3 years ago
3 0
Given:
Profit : 15,000,000
Cost: 30 per basketball hoop
production: 1 million hoops
price: 50 - 5x²

Profit = Sales - Cost
15,000,000 = sales - 30(1,000,000)
15,000,000 + 30,000,000 = sales
45,000,000 = sales

45,000,000 / 1,000,000 = 45 sales price.




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Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

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These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

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P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

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sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

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Round this value however you need to.

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